在Java中将类作为参数传递给SOAP web服务

在Java中将类作为参数传递给SOAP web服务,java,web-services,soap,parameter-passing,Java,Web Services,Soap,Parameter Passing,嗨,我想把一个类作为参数传递给Web服务。 这是我的web服务代码: <xs:complexType name="RegisterStudent"> <xs:sequence> <xs:element name="student" type="tns:student" minOccurs="0"/> <xs:element name="user" type="xs:string" minOccurs="0"/> </xs:sequence&g

嗨,我想把一个类作为参数传递给Web服务。 这是我的web服务代码:

<xs:complexType name="RegisterStudent">
<xs:sequence>
<xs:element name="student" type="tns:student" minOccurs="0"/>
<xs:element name="user" type="xs:string" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
}

这是我的学生课:

Public Class Student implements Serializable{
  private int age;
  private String name;
  public Student(){}
  public Student(int age, String name){
    this.age = age;
    this.name = name;
  }
  //setter and getter methods come here.
  //...
}
运行此操作后,出现以下错误: '无法序列化:Student@4329d250’请帮忙


提前感谢

所以我想好了该怎么做: 首先,使类可序列化

Public Class Student implements KvmSerializable{

private int age;
private String name;

public Student(){}

public Student(int age, String name){
   this.age = age;
   this.name = name;
  }
  //setter and getter methods come here.
  //...

  public Object getProperty(int arg0) {
      switch(arg0){
      case 0: 
          return getAge();
      case 1:
          return getName();
      }
      return null;
  }

  public int getPropertyCount() {
      return 2;
  }

  public void setProperty(int index, Object value) {
      switch(index){
      case 0 :
         age = value.toString();
         break;
      case 1 :
         name = value.toString();
         break;
      default:
         break;
      }
  }
}
WebService方法如下所示:

public static String registerStudentClass(Student stud) {
  soapAction="http://auth.ws.df.com/RegisterStudent";
  methodName="RegisterStudent";
  String resTxt = null;

  //new change
  PropertyInfo pi = new PropertyInfo();
  pi.setName("stud");
  pi.setValue(stud);
  pi.setType(stud.getClass());

  SoapObject request = new SoapObject(NAMESPACE, methodName);
  request.addProperty(pi);

  SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
  SoapEnvelope.VER11);
  envelope.setOutputSoapObject(request);//new change
  envelope.addMapping(NAMESPACE, "Student", new Student().getClass());
  HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
  System.out.println("androidHttpTransport envelope");

  try{
      androidHttpTransport.call(soapAction, envelope);
      SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
      resTxt = response.toString();
   }catch(Exception e){
      e.printStackTrace();
      resTxt = "Error occured\n"+e;
  }

  return resTxt;
}
我假设响应是一个文本,例如1-成功注册
2-注册失败,etc

是否用
Serializable
标记
Student
public static String registerStudentClass(Student stud) {
  soapAction="http://auth.ws.df.com/RegisterStudent";
  methodName="RegisterStudent";
  String resTxt = null;

  //new change
  PropertyInfo pi = new PropertyInfo();
  pi.setName("stud");
  pi.setValue(stud);
  pi.setType(stud.getClass());

  SoapObject request = new SoapObject(NAMESPACE, methodName);
  request.addProperty(pi);

  SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
  SoapEnvelope.VER11);
  envelope.setOutputSoapObject(request);//new change
  envelope.addMapping(NAMESPACE, "Student", new Student().getClass());
  HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
  System.out.println("androidHttpTransport envelope");

  try{
      androidHttpTransport.call(soapAction, envelope);
      SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
      resTxt = response.toString();
   }catch(Exception e){
      e.printStackTrace();
      resTxt = "Error occured\n"+e;
  }

  return resTxt;
}