Java iOS5:无法使用NSJSONSerialization从JSON读取值

我正在尝试解析JSON数据。数据是一个数组，其中包含对象。 这是我从URL获得的JSON数组：

["{content:Airfare}",
"{content:Dues \/ Subscriptions}",
"{content:Education \/ Training}",
"{content:Entertainment}",
"{content:GS-OCWD}",
"{content:GS-OCWE}",
"{content:GS-Shift A}",
"{content:GS-Shift B}",
"{content:GS-Shift C}",
"{content:Ground Transportation}",
"{content:Legal Fees}",
"{content:Lodging}",
"{content:Meals}",
"{content:Mileage}",
"{content:Office Supplies}",
"{content:Other Expenses}",
"{content:Prof. Dues & Memberships}",
"{content:Rental Car}",
"{content:Telephone}",
"{content:Telephone \/ Internet}",
"{content:Tolls \/ Parking}"]

public JSONArray getAllNotes()
    {
        PreparedStatement prepStmt = null;
        List<Note> notes = new ArrayList<Note>();
        try {
            String cSQL = "SELECT EXPENDITURE_TYPE FROM PA_ONLINE_EXPENDITURE_TYPES_V;
            prepStmt = connection.prepareStatement(cSQL);
            ResultSet result = prepStmt.executeQuery();
            while (result.next())
            {
                Note note = new Note();
                //note.setNoteId(result.getInt(1));
                note.setContent(result.getString(1));
                //note.setCreatedDate( new java.util.Date(result.getDate(3).getTime()));
                notes.add(note);
            }
            return new JSONArray(notes);
        } catch (SQLException e) {
            e.printStackTrace();
            prepStmt = null;
            return null;
        }
    }                       

这是在my.m文件中解析JSON数组的代码

NSError *error = nil;
    NSData *jsonData = [NSData dataWithContentsOfURL:[NSURL URLWithString:@"http://localhost:8080/de.vogella.jersey.final/rest/notes"]];    


    NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData: jsonData options: NSJSONReadingMutableContainers error: &error];

    if (!jsonArray) {
        NSLog(@"Error parsing JSON: %@",error);
    } else {
        for(NSDictionary *item in jsonArray) {
            NSLog(@"Item: %@", [item objectForKey:@"content"]);
            [_identificationTypes1 addObject:item];
        }

    }

public JSONArray getAllNotes()
    {
        PreparedStatement prepStmt = null;
        List<Note> notes = new ArrayList<Note>();
        try {
            String cSQL = "SELECT EXPENDITURE_TYPE FROM PA_ONLINE_EXPENDITURE_TYPES_V;
            prepStmt = connection.prepareStatement(cSQL);
            ResultSet result = prepStmt.executeQuery();
            while (result.next())
            {
                Note note = new Note();
                //note.setNoteId(result.getInt(1));
                note.setContent(result.getString(1));
                //note.setCreatedDate( new java.util.Date(result.getDate(3).getTime()));
                notes.add(note);
            }
            return new JSONArray(notes);
        } catch (SQLException e) {
            e.printStackTrace();
            prepStmt = null;
            return null;
        }
    }                       

当行

NSLog（@“Item:%@，[Item objectForKey:@“content”]）时[\uu NSCFString objectForKey:]：无法识别的选择器时，将执行code>。它无法读取关键内容。如果我将行更改为
NSLog（@“Item:%@”，Item）
我可以看到所有的值，比如
{content:Airfare}
。我只需要机票的价格。有人能帮我吗

public JSONArray getAllNotes()
    {
        PreparedStatement prepStmt = null;
        List<Note> notes = new ArrayList<Note>();
        try {
            String cSQL = "SELECT EXPENDITURE_TYPE FROM PA_ONLINE_EXPENDITURE_TYPES_V;
            prepStmt = connection.prepareStatement(cSQL);
            ResultSet result = prepStmt.executeQuery();
            while (result.next())
            {
                Note note = new Note();
                //note.setNoteId(result.getInt(1));
                note.setContent(result.getString(1));
                //note.setCreatedDate( new java.util.Date(result.getDate(3).getTime()));
                notes.add(note);
            }
            return new JSONArray(notes);
        } catch (SQLException e) {
            e.printStackTrace();
            prepStmt = null;
            return null;
        }
    }                       

这是生成JSON的代码。我正在使用Jersey和JAVA。
你能帮我从URL获取JSON格式吗？这是我的DAO代码：

public JSONArray getAllNotes()
    {
        PreparedStatement prepStmt = null;
        List<Note> notes = new ArrayList<Note>();
        try {
            String cSQL = "SELECT EXPENDITURE_TYPE FROM PA_ONLINE_EXPENDITURE_TYPES_V;
            prepStmt = connection.prepareStatement(cSQL);
            ResultSet result = prepStmt.executeQuery();
            while (result.next())
            {
                Note note = new Note();
                //note.setNoteId(result.getInt(1));
                note.setContent(result.getString(1));
                //note.setCreatedDate( new java.util.Date(result.getDate(3).getTime()));
                notes.add(note);
            }
            return new JSONArray(notes);
        } catch (SQLException e) {
            e.printStackTrace();
            prepStmt = null;
            return null;
        }
    }                       

这是调用DAO方法的方法：

public JSONArray getAllNotes()
    {
        PreparedStatement prepStmt = null;
        List<Note> notes = new ArrayList<Note>();
        try {
            String cSQL = "SELECT EXPENDITURE_TYPE FROM PA_ONLINE_EXPENDITURE_TYPES_V;
            prepStmt = connection.prepareStatement(cSQL);
            ResultSet result = prepStmt.executeQuery();
            while (result.next())
            {
                Note note = new Note();
                //note.setNoteId(result.getInt(1));
                note.setContent(result.getString(1));
                //note.setCreatedDate( new java.util.Date(result.getDate(3).getTime()));
                notes.add(note);
            }
            return new JSONArray(notes);
        } catch (SQLException e) {
            e.printStackTrace();
            prepStmt = null;
            return null;
        }
    }                       

@GET

 @Produces({MediaType.APPLICATION_JSON})
        public JSONArray getNotes() {
            return dao.getAllNotes();
        }     

你的JSON是错误的。这只是一个字符串数组，这就是为什么会出现这个错误。它真正应该是这样的：

public JSONArray getAllNotes()
    {
        PreparedStatement prepStmt = null;
        List<Note> notes = new ArrayList<Note>();
        try {
            String cSQL = "SELECT EXPENDITURE_TYPE FROM PA_ONLINE_EXPENDITURE_TYPES_V;
            prepStmt = connection.prepareStatement(cSQL);
            ResultSet result = prepStmt.executeQuery();
            while (result.next())
            {
                Note note = new Note();
                //note.setNoteId(result.getInt(1));
                note.setContent(result.getString(1));
                //note.setCreatedDate( new java.util.Date(result.getDate(3).getTime()));
                notes.add(note);
            }
            return new JSONArray(notes);
        } catch (SQLException e) {
            e.printStackTrace();
            prepStmt = null;
            return null;
        }
    }                       

[{"content":"Airfare"},
{"content":"Dues \/ Subscriptions"},
{"content":"Education \/ Training"},
... etc]

如何创建正确的格式？你能帮我一下吗我是新来的我想说的是问题在于你从你的url得到的回复。在您的例子中，您从
http://localhost:8080/de.vogella.jersey.final/rest/notes
是罪魁祸首。您的objc代码没有问题。您能帮助我使用URL中的JSON格式吗？这是我的DAO代码。您是如何生成JSON的？它是服务器上的文件还是动态创建的？@user1342592对不起，伙计，JAVA不是我的事。我建议在你的问题中添加一个java标记，以吸引懂这种语言的人。