Java ApacheHttpClient(4.1及更新版本):如何进行基本身份验证?
如何为httpClient库的默认客户端添加基本身份验证?我看到过使用Java ApacheHttpClient(4.1及更新版本):如何进行基本身份验证?,java,apache-httpclient-4.x,apache-httpcomponents,Java,Apache Httpclient 4.x,Apache Httpcomponents,如何为httpClient库的默认客户端添加基本身份验证?我看到过使用client.getCredentialProvider()的示例,但是我认为所有这些方法都适用于库版本4.0.1或3.x。有没有一个新的例子来说明如何做到这一点?非常感谢。我们使用HttpClient进行基本身份验证,但不使用CredentialProvider。代码如下: HttpClient client = factory.getHttpClient(); //or any method to get a client
client.getCredentialProvider()
的示例,但是我认为所有这些方法都适用于库版本4.0.1或3.x。有没有一个新的例子来说明如何做到这一点?非常感谢。我们使用HttpClient
进行基本身份验证,但不使用CredentialProvider
。代码如下:
HttpClient client = factory.getHttpClient(); //or any method to get a client instance
Credentials credentials = new UsernamePasswordCredentials(username, password);
client.getState().setCredentials(AuthScope.ANY, credentials);
更新:
注释中指出,
HttpClient.getState()
方法在中可用。但是,不支持该方法。您不是从网站下载了示例吗?示例如下:httpcomponents-client-4.1.3\examples\org\apache\http\examples\client
关于https,请参见ClientAuthentication.java:
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* contributor license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright ownership.
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package org.apache.http.examples.client;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.auth.AuthScope;
import org.apache.http.auth.UsernamePasswordCredentials;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
/**
* A simple example that uses HttpClient to execute an HTTP request against
* a target site that requires user authentication.
*/
public class ClientAuthentication {
public static void main(String[] args) throws Exception {
DefaultHttpClient httpclient = new DefaultHttpClient();
try {
httpclient.getCredentialsProvider().setCredentials(
new AuthScope("localhost", 443),
new UsernamePasswordCredentials("username", "password"));
HttpGet httpget = new HttpGet("https://localhost/protected");
System.out.println("executing request" + httpget.getRequestLine());
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
System.out.println("----------------------------------------");
System.out.println(response.getStatusLine());
if (entity != null) {
System.out.println("Response content length: " + entity.getContentLength());
}
EntityUtils.consume(entity);
} finally {
// When HttpClient instance is no longer needed,
// shut down the connection manager to ensure
// immediate deallocation of all system resources
httpclient.getConnectionManager().shutdown();
}
}
}
DefaultHttpClient具有getCredentialsProvider(),但HttpClient没有。 你需要申报 DefaultHttpClient客户端=。。。 而不是
HttpClient=…4.3的另一个现代选项是使用Fluent扩展:
CredentialsProvider credentialsProvider = new BasicCredentialsProvider();
credentialsProvider.setCredentials(AuthScope.ANY,
new UsernamePasswordCredentials("username", "password"));
CloseableHttpClient httpClient =
HttpClientBuilder.create().setDefaultCredentialsProvider(credentialsProvider).build();
Executor executor = Executor.newInstance()
.auth(new HttpHost("somehost"), "username", "password")
.auth(new HttpHost("securehost", 443, "https"), "username", "password") // https example
.auth(new HttpHost("myproxy", 8080), "username", "password")
.authPreemptive(new HttpHost("myproxy", 8080));
String content = executor.execute(Request.Get("http://somehost/"))
.returnContent().asString();
我需要使用基本身份验证调用URL,这也需要代理设置。 这就是我的工作
import java.io.IOException;
import java.io.InputStream;
import java.io.StringReader;
import java.util.HashMap;
import java.util.Map;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.commons.httpclient.Credentials;
import org.apache.commons.httpclient.HostConfiguration;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.UsernamePasswordCredentials;
import org.apache.commons.httpclient.auth.AuthScope;
import org.apache.commons.httpclient.methods.GetMethod;
import org.w3c.dom.*;
import javax.xml.parsers.*;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class TestResponse {
public final static String TESTURL="https://myURL";
private static final String PROXY_HOST = "www2.proxyXYS";
private static final int PROXY_PORT = 8080;
public static void main (String args[])
{
HttpClient client = new HttpClient();
HttpMethod method = new GetMethod(TESTURL);
HostConfiguration config = client.getHostConfiguration();
config.setProxy(PROXY_HOST, PROXY_PORT);
String username = "User";
String password = "Pa55w0rd";
Credentials credentials = new UsernamePasswordCredentials(username, password);
AuthScope authScope = new AuthScope(PROXY_HOST, PROXY_PORT);
client.getState().setProxyCredentials(authScope, credentials);
client.getState().setCredentials(AuthScope.ANY, credentials);
try {
client.executeMethod(method);
String response = method.getResponseBodyAsString();
if (method.getStatusCode() == HttpStatus.SC_OK) {
response = method.getResponseBodyAsString();
}
} catch (IOException e) {
e.printStackTrace();
} finally {
method.releaseConnection();
}
}
}
请看这是我找到的最好的例子。。。比apache文档要好得多:这很好,但是HttpClient.getState()在4.x代码中不存在。这只适用于3.1及更早版本。我是唯一一个对为什么这是公认的答案感到困惑的人吗?这是v4.3的最佳答案。请注意,它会将凭据先发制人地发送到所有URL。要解决artbristol的问题,请更改AuthScope。@artbristol仅在您配置了先发制人身份验证时,对吗@是的,我想你是对的。这会将凭据发送到任何需要凭据的服务器,但不会发送到其他服务器。
DefaultHttpClient
现在在4.3中被弃用,尽管它只在4.0中引入!DefaultHttpClient在4.x中不推荐使用。您可以使用中的示例。DefaultHttpClient仅在4.3中被弃用。在4.1中,它并没有被弃用,因为在https连接上要想让它工作起来有点困难,所以不需要忘记在HttpHost(新的HttpHost(“somehost”,443,“https”)上添加端口和方案,因为默认端口和方案是80,http。Executer
的完整导入路径是什么?我在中遇到了一个错误。newInstance()
。编译器说这不存在。您使用的是哪个版本的JDK?org.apache.http.client.fluent.Executor
import java.io.IOException;
import java.io.InputStream;
import java.io.StringReader;
import java.util.HashMap;
import java.util.Map;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.commons.httpclient.Credentials;
import org.apache.commons.httpclient.HostConfiguration;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.UsernamePasswordCredentials;
import org.apache.commons.httpclient.auth.AuthScope;
import org.apache.commons.httpclient.methods.GetMethod;
import org.w3c.dom.*;
import javax.xml.parsers.*;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class TestResponse {
public final static String TESTURL="https://myURL";
private static final String PROXY_HOST = "www2.proxyXYS";
private static final int PROXY_PORT = 8080;
public static void main (String args[])
{
HttpClient client = new HttpClient();
HttpMethod method = new GetMethod(TESTURL);
HostConfiguration config = client.getHostConfiguration();
config.setProxy(PROXY_HOST, PROXY_PORT);
String username = "User";
String password = "Pa55w0rd";
Credentials credentials = new UsernamePasswordCredentials(username, password);
AuthScope authScope = new AuthScope(PROXY_HOST, PROXY_PORT);
client.getState().setProxyCredentials(authScope, credentials);
client.getState().setCredentials(AuthScope.ANY, credentials);
try {
client.executeMethod(method);
String response = method.getResponseBodyAsString();
if (method.getStatusCode() == HttpStatus.SC_OK) {
response = method.getResponseBodyAsString();
}
} catch (IOException e) {
e.printStackTrace();
} finally {
method.releaseConnection();
}
}
}