Javascript 如何测试表单提交与笑话和酶的反应?
我正在学习带钩子的reactjs表单,现在我想用jest和Ezyme测试提交表单 这是我的登录组件Javascript 如何测试表单提交与笑话和酶的反应?,javascript,reactjs,unit-testing,jestjs,enzyme,Javascript,Reactjs,Unit Testing,Jestjs,Enzyme,我正在学习带钩子的reactjs表单,现在我想用jest和Ezyme测试提交表单 这是我的登录组件 import React from 'react' function Login() { const [email, setEmail] = useState(''); const [password, setPassword] = useState(''); const handleSubmit = async (e) => { e.preven
import React from 'react'
function Login() {
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
const handleSubmit = async (e) => {
e.preventDefault();
// ....api calLS
}
return (
<div>
<form onSubmit={handleSubmit} className="login">
<input type="email" id="email-input" name="email" value={email} onChange={e => setEmail(e.target.value)} />
<input type="password" id="password-input" name="password" value={password} onChange={e =>setPassword(e.target.value)} />
<input type="submit" value="Submit" />
</form>
</div>
)
}
export default Login
从“React”导入React
函数登录(){
const[email,setEmail]=useState(“”);
const[password,setPassword]=useState(“”);
const handleSubmit=async(e)=>{
e、 预防默认值();
//..api调用
}
返回(
setEmail(e.target.value)}/>
setPassword(e.target.value)}/>
)
}
导出默认登录名
这是login.test.js文件
describe('my sweet test', () => {
it('clicks it', () => {
const wrapper = shallow(<Login />);
const updatedEmailInput = simulateChangeOnInput(wrapper, 'input#email-input', 'blah@gmail.com')
const updatedPasswordInput = simulateChangeOnInput(wrapper, 'input#password-input', 'death');
expect(updatedEmailInput.props().value).toEqual('blah@gmail.com');
expect(updatedPasswordInput.props().value).toEqual('death');
const instance = wrapper.instance()
const spy = jest.spyOn(instance, 'handleSubmit')
instance.forceUpdate();
const submitBtn = app.find('#sign-in')
submitBtn.simulate('click')
expect(spy).toHaveBeenCalled()
})
})
description('my sweet test',()=>{
它('点击它',()=>{
常量包装器=浅();
const updatedEmailInput=simulateChangeOnInput(包装器,'input#email input','blah@gmail.com')
const updatedPasswordInput=simulateChangeOnInput(包装器,'input#password input','death');
expect(updatedEmailInput.props().value).toEqual('blah@gmail.com');
expect(updatedPasswordInput.props().value).toEqual('death');
const instance=wrapper.instance()
const spy=jest.spyOn(实例'handleSubmit')
forceUpdate();
const submitBtn=app.find(“#登录”)
submitBtn.simulate('单击')
expect(spy).tohavebeincalled()
})
})
不幸的是,当我运行npm测试时,我得到了以下错误。
我需要做些什么来解决这个错误,或者有人能提供一个关于如何测试表单提交的教程吗?在文档中,有人说不能将shall.instance()用于功能组件
它将返回空值:
关于这个问题,以前也有一个答案
您可以将经过验证的函数handleSubmit传递给以prop身份登录,如图所示
//单元测试
描述('SomeComponent'()=>{
它('单击按钮时验证模型',()=>{
const handleSubmit=jest.fn();
常量包装器=装入(
);
const instance=wrapper.instance();
const submitBtn=app.find(“#登录”)
submitBtn.simulate('单击')
expect(handleSubmit).tohavebeincall();
});
}
您需要在登录组件中调用此测试函数handleSubmit,作为onSubmit的一部分,或者从上层组件导出整个onSubmit。导入部分登录函数的登录代码示例
import React from 'react'
function Login( {handleSubmit}) {
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
const onSubmit = async (e) => {
if (handleSubmit) {
handleSubmit()
}
e.preventDefault();
// ....api calLS
}
return (
<div>
<form onSubmit={onSubmit} className="login">
<input type="email" id="email-input" name="email" value={email} onChange={e => setEmail(e.target.value)} />
<input type="password" id="password-input" name="password" value={password} onChange={e =>setPassword(e.target.value)} />
<input type="submit" value="Submit" />
</form>
</div>
)
}
export default Login
从“React”导入React
函数登录({handleSubmit}){
const[email,setEmail]=useState(“”);
const[password,setPassword]=useState(“”);
const onSubmit=async(e)=>{
if(handleSubmit){
handleSubmit()
}
e、 预防默认值();
//..api调用
}
返回(
setEmail(e.target.value)}/>
setPassword(e.target.value)}/>
)
}
导出默认登录名
导入提交功能的登录代码示例
import React from 'react'
function Login( {handleSubmit}) {
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
// handleSubmit is imported with props
return (
<div>
<form onSubmit={handleSubmit} className="login">
<input type="email" id="email-input" name="email" value={email} onChange={e => setEmail(e.target.value)} />
<input type="password" id="password-input" name="password" value={password} onChange={e =>setPassword(e.target.value)} />
<input type="submit" value="Submit" />
</form>
</div>
)
}
export default Login
从“React”导入React
函数登录({handleSubmit}){
const[email,setEmail]=useState(“”);
const[password,setPassword]=useState(“”);
//handleSubmit随道具一起导入
返回(
setEmail(e.target.value)}/>
setPassword(e.target.value)}/>
)
}
导出默认登录名
在文档中提到,不能将shall.instance()用于功能组件
它将返回空值:
关于这个问题,以前也有一个答案
您可以将经过验证的函数handleSubmit传递给以prop身份登录,如图所示
//单元测试
描述('SomeComponent'()=>{
它('单击按钮时验证模型',()=>{
const handleSubmit=jest.fn();
常量包装器=装入(
);
const instance=wrapper.instance();
const submitBtn=app.find(“#登录”)
submitBtn.simulate('单击')
expect(handleSubmit).tohavebeincall();
});
}
您需要在登录组件中调用此测试函数handleSubmit,作为onSubmit的一部分,或者从上层组件导出整个onSubmit。导入部分登录函数的登录代码示例
import React from 'react'
function Login( {handleSubmit}) {
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
const onSubmit = async (e) => {
if (handleSubmit) {
handleSubmit()
}
e.preventDefault();
// ....api calLS
}
return (
<div>
<form onSubmit={onSubmit} className="login">
<input type="email" id="email-input" name="email" value={email} onChange={e => setEmail(e.target.value)} />
<input type="password" id="password-input" name="password" value={password} onChange={e =>setPassword(e.target.value)} />
<input type="submit" value="Submit" />
</form>
</div>
)
}
export default Login
从“React”导入React
函数登录({handleSubmit}){
const[email,setEmail]=useState(“”);
const[password,setPassword]=useState(“”);
const onSubmit=async(e)=>{
if(handleSubmit){
handleSubmit()
}
e、 预防默认值();
//..api调用
}
返回(
setEmail(e.target.value)}/>
setPassword(e.target.value)}/>
)
}
导出默认登录名
导入提交功能的登录代码示例
import React from 'react'
function Login( {handleSubmit}) {
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
// handleSubmit is imported with props
return (
<div>
<form onSubmit={handleSubmit} className="login">
<input type="email" id="email-input" name="email" value={email} onChange={e => setEmail(e.target.value)} />
<input type="password" id="password-input" name="password" value={password} onChange={e =>setPassword(e.target.value)} />
<input type="submit" value="Submit" />
</form>
</div>
)
}
export default Login
从“React”导入React
函数登录({handleSubmit}){
const[email,setEmail]=useState(“”);
const[password,setPassword]=useState(“”);
//handleSubmit随道具一起导入
返回(
setEmail(e.target.value)}/>
setPassword(e.target.value)}/>
)
}
导出默认登录名
那么,我需要做什么来测试我的表单提交?你可以通过验证函数作为道具,如此处所示。你需要在登录组件中使用此test handleSubmit函数。你可以使用此test handleSubmit函数来测试我的表单提交。我需要做什么来测试我的表单提交?你可以通过验证函数作为道具,如此处所示。你需要使用此test handleSubmit函数登录组件中的函数可用于无次调用