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Javascript 谷歌说代码无效,我的错误在哪里?_Javascript - Fatal编程技术网

Javascript 谷歌说代码无效,我的错误在哪里?

Javascript 谷歌说代码无效,我的错误在哪里?,javascript,Javascript,谷歌表示,它无法读取以下代码块中的hasweated属性 var movie = [ { title: "Iron Man", hasWatched: true, rating: "5.0", }, { title: "Mad Max", hasWatched: false, rating: "2.0", } ] 您没有将参数传递给buildString()函数 在forEach中调用bui

谷歌表示,它无法读取以下代码块中的hasweated属性

var movie = [
    {
      title: "Iron Man",
      hasWatched: true,
      rating: "5.0",
    },
    {
      title: "Mad Max",
      hasWatched: false,
      rating: "2.0",
    }
]
您没有将参数传递给buildString()函数


forEach
中调用
buildString()无参数
function buildString (movie){
    var result = "You have ";
    if(movie.hasWatched){ 
        result += "watched ";
    } else {
        result += "not watched ";
    }
    result += "\"" + movie.title + "\" - ";
    result += movie.rating + " stars"
    return result;
}

movie.forEach(function(movie){
    buildString();
    console.log(buildString(movie));
});
movie.forEach(function(movie){
buildString(movie);
console.log(buildString(movie));
});