Javascript 在Json中搜索并获得有限的搜索结果

我有一个JSON文件，看起来像这样

[{
    "id": "2",
    "word": "Aam",
    "type": "n.",
    "descr": " A Dutch and German measure of liquids, varying in different cities, being at Amsterdam about 41 wine gallons, at Antwerp 36 1\/2, at Hamburg 38 1\/4.",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aam"
}, {
    "id": "3",
    "word": "Aard-vark",
    "type": "n.",
    "descr": " An edentate mammal, of the genus Orycteropus, somewhat resembling a pig, common in some parts of Southern Africa. It burrows in the ground, and feeds entirely on ants, which it catches with its long, slimy tongue.",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aar"
}, {
    "id": "4",
    "word": "Aard-wolf",
    "type": "n.",
    "descr": " A carnivorous quadruped (Proteles Lalandii), of South Africa, resembling the fox and hyena. See Proteles.",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aar"
}, {
    "id": "5",
    "word": "Aaronic",
    "type": "a.",
    "descr": " Alt. of Aaronical",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aar"
}, {
    "id": "6",
    "word": "Aaronical",
    "type": "a.",
    "descr": " Pertaining to Aaron, the first high priest of the Jews.",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aar"
}, {
    "id": "7",
    "word": "Aarons rod",
    "type": "",
    "descr": " A rod with one serpent twined around it, thus differing from the caduceus of Mercury, which has two.",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aar"
}, {
    "id": "8",
    "word": "Aarons rod",
    "type": "",
    "descr": " A plant with a tall flowering stem; esp. the great mullein, or hag-taper, and the golden-rod.",
    "track": "a",
    "track_2": "Aa",
    "track_3": "Aar"
}]

我想通过word=“Aa”、track\u 2=“Aa”、track\u 3=“aar”获得前2个或3个结果。。我该怎么做

我需要什么
1.Json中的字符串查询 2.收效有限 3.我想按2-3个条件在json文件中搜索

我在试这个

$(window).load(function() {

    $('#search').keyup(function() {
        var searchField = $('#search').val();

        $.getJSON('files/aa.json', function(data) {

            var jsonArrr = data;
            var matchMe = new RegExp('^' + searchField, 'i');
            var matches = [];

            for (var i in jsonArrr) {
                if (jsonArrr[i].word.search(matchMe) > -1) {
                    matches.push({
                        'id': jsonArrr[i].word,
                        'word': jsonArrr[i].word
                    });
                }
            }

            for (var i in matches) {
                console.log(matches[i].word);
            }
        });
    });
});

---

有没有办法通过扩展一些代码来获得所需的内容？

在这部分添加几行代码-

var matches = [];

for (var i in jsonArrr) {

    if ( jsonArrr[i].word.search(matchMe) > -1 && jsonArrr[i].type.search(matchType) > -1 ) { // define matchType for the type keyword

            matches.push( {'id': jsonArrr[i].word , 'word': jsonArrr[i].word} );

    }

if(matches.length == 2) { // replace 2 with your number of results - 1
break;
}

}

---

有什么理由不将json解析为对象而只是比较属性吗？我认为这一行-

'id'：jsonarr[I]。word

应该改为

'id'：jsonarr[I]。id

我正在使用json文件作为firefoxOS的脱机数据库，这就是为什么我将json解析为对象@Shillyit！但我也想按2-3个条件在json文件中搜索。。有解决方案吗？2-3个条件更多？？例子？？您正在搜索每个对象的

word

属性中的字符串，是否还要搜索type、desc等？？？很抱歉答复太晚，是。。我想同时使用类型和单词搜索。。。但是我不需要descr搜索..使用相同的东西--

if（jsonArrr[i].type.search（matchMe）>-1{…}

。对于和条件（匹配类型和单词）

if（jsonarr[i].word.search（matchMe）>-1&&jsonarr[i].type.search（matchMe）>-1{……}