Javascript 将数组值从特定字符修剪为特定字符
如何从数组中获取特定值? i、 e 输出必须是:Javascript 将数组值从特定字符修剪为特定字符,javascript,angular,Javascript,Angular,如何从数组中获取特定值? i、 e 输出必须是: "Names": [ "name", "Type", "Option", "Pointer" ] 试着这样做: export class AppComponent { Names = [ "Name[name]", "Result[Type]", "Validation[Option]", "Status[Pointer]" ] construct
"Names": [
"name",
"Type",
"Option",
"Pointer"
]
试着这样做:
export class AppComponent {
Names = [
"Name[name]",
"Result[Type]",
"Validation[Option]",
"Status[Pointer]"
]
constructor() {
var modifiedNames = this.Names.map(x => x.split('[').pop().split(']')[0])
console.log(modifiedNames)
}
}
请参见您可以使用方法并根据开始和结束括号抓取子字符串。要在数组use函数的每个元素上迭代,它将创建一个新数组,其中包含对调用数组中的每个元素调用所提供函数的结果
const arr = [
"Name[name]",
"Result[Type]",
"Validation[Option]",
"Status[Pointer]"
]
let result = arr.map((a)=>{ return a.substring(a.indexOf("[") + 1 , a.indexOf("]")) });
console.log(result);
您可以在数组中循环并使用以下正则表达式来获得所需的输出
const array = [
"Name[name]",
"Result[Type]",
"Validation[Option]",
"Status[Pointer]"
];
var regexTest = new RegExp(/\[([^\]]+)\]/);
var newArray = array.map(e => regexTest.exec(e)[1]);
链接正在运行的子字符串和索引:
let newArray = [];
for(var i=0; i<array.length; i++){
var s = array[i];
var n = s.indexOf('[');
s = s.substring(n+1, s.length-1);
newArray.push(s);
}
让newArray=[];
对于(var i=0;i)您是否尝试过该解决方案?
const array = [
"Name[name]",
"Result[Type]",
"Validation[Option]",
"Status[Pointer]"
];
var regexTest = new RegExp(/\[([^\]]+)\]/);
var newArray = array.map(e => regexTest.exec(e)[1]);
let newArray = [];
for(var i=0; i<array.length; i++){
var s = array[i];
var n = s.indexOf('[');
s = s.substring(n+1, s.length-1);
newArray.push(s);
}
let newArray = [];
for(var i=0; i<array.length; i++){
newArray.push(array[i].substring(array[i].indexOf('[')+1, array[i].length-1));
}