Javascript 在AngularJS中格式化浮点数字而不丢失精度

在AngularJS中，我如何在HTML页面上输出一个浮点数而不丢失精度，并且不使用0进行不必要的填充

我考虑过“number”ng filter（），但fractionSize参数会产生固定数量的小数：

{{ number_expression | number : fractionSize}}

我在寻找其他各种语言中被称为“精确再现性”、“规范字符串表示”、repr、往返等等的内容，但我还没有找到AngularJS的类似内容

例如：

• 1=>“1”
• 1.2=>“1.2”
• 1.23456789=>“1.23456789”

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您可以捕获不带尾随零的零件，并将其用于正则表达式替换。大概您希望保留一个尾随的零（例如“78.0”）以保持整洁，而不是以十进制分隔符（例如“78”）结尾

解释来自：

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我自己偶然发现了一个显而易见的解决办法！完全删除“number”ng过滤器将导致AngularJS根据我的要求将表达式简单地转换为字符串

所以

而不是

{{ number_expression | number : fractionSize}}

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你能给出一些输入和输出数值的例子吗？谢谢，我没有考虑过这种方法。它肯定会起作用，正如您所指出的，它提供了定制输出的完全控制，例如，包含最小数量的小数。然而，正如我在下面的回答中所说，AngularJS已经通过完全省略“number”ng过滤器来支持我想要的。

/([0-9]+\.[0-9]+?)(0*)$/
    1st Capturing group ([0-9]+\.[0-9]+?)
        [0-9]+ match a single character present in the list below
            Quantifier: + Between one and unlimited times, as many times as possible, giving back as needed [greedy]
            0-9 a single character in the range between 0 and 9
        \. matches the character . literally
        [0-9]+? match a single character present in the list below
            Quantifier: +? Between one and unlimited times, as few times as possible, expanding as needed [lazy]
            0-9 a single character in the range between 0 and 9
    2nd Capturing group (0*)
        0* matches the character 0 literally
            Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy]
    $ assert position at end of the string

{{ number_expression }}

{{ number_expression | number : fractionSize}}