Javascript Promise.map不';不返回值
我是新来的 这是我的密码Javascript Promise.map不';不返回值,javascript,node.js,promise,bluebird,Javascript,Node.js,Promise,Bluebird,我是新来的 这是我的密码 compileChatnameArray(company_id, paramArr) { const Model = this; let userObjIdArr = []; return Promise.map(paramArr, function (paramObj) { const chat_name = paramObj.customer_id; const full_name = paramObj.fi
compileChatnameArray(company_id, paramArr) {
const Model = this;
let userObjIdArr = [];
return Promise.map(paramArr, function (paramObj) {
const chat_name = paramObj.customer_id;
const full_name = paramObj.firstname + paramObj.lastname;
let queryObj = Model.findOne({
chat_name: chat_name
})
.lean()
.select('_id')
.exec()
.then((user) = > {
if (user) {
userObjIdArr.push(user._id);
return userObjIdArr;
} else {
var bodyParam = {
_company_id: company_id,
chat_name: chat_name,
full_name: full_name
};
Model.add(bodyParam)
.then((newUser) = > {
userObjIdArr.push(newUser._id);
return userObjIdArr;
})
}
});
})
.then((userObjIdArr) = > {
debug(userObjIdArr);
return Promise.resolve(userObjIdArr);
})
}
问题是debug(userObjIdArr)代码>
为我打印[未定义,未定义,未定义,未定义,未定义]
。
(我的数组有5个对象)
//编辑部分
我在map函数中添加了Promise-resolve部分,它提供了有线结果。我能理解我只是在一个简短的逻辑后面,但我不知道在哪里
compileChatnameArray(company_id, paramArr) {
const Model = this;
let userObjIdArr = [];
return Promise.map(paramArr, function(paramObj) {
const chat_name = paramObj.customer_id;
const full_name = paramObj.firstname + paramObj.lastname;
let queryObj = Model.findOne({ chat_name: chat_name})
.lean()
.select('_id')
.exec();
return new Promise(function(resolve, reject) {
// code starts here
queryObj.then((user) => {
if(user) {
userObjIdArr.push(user._id)
resolve(userObjIdArr);
} else {
//add user here
var bodyParam = {
_company_id : company_id,
chat_name : chat_name,
full_name : full_name
};
Model.add(bodyParam)
.then((newUser) => {
userObjIdArr.push(newUser._id)
resolve(userObjIdArr);
})
.catch((err) => {
reject(err);
});
}
});
queryObj.catch((err) => {
reject(err);
})
})
});
}
现在我得到了以下结果
[
[
“589d598f07e32926b4ae9d6b”,
“589d598f07e32926b4ae9d6c”,
“589d598f07e32926b4ae9d6e”,
“589d598f07e32926b4ae9d6f”,
“589d598f07e32926b4ae9d6d”
],
[
“589d598f07e32926b4ae9d6b”,
“589d598f07e32926b4ae9d6c”,
“589d598f07e32926b4ae9d6e”,
“589d598f07e32926b4ae9d6f”,
“589d598f07e32926b4ae9d6d”
],
[
“589d598f07e32926b4ae9d6b”,
“589d598f07e32926b4ae9d6c”,
“589d598f07e32926b4ae9d6e”,
“589d598f07e32926b4ae9d6f”,
“589d598f07e32926b4ae9d6d”
],
[
“589d598f07e32926b4ae9d6b”,
“589d598f07e32926b4ae9d6c”,
“589d598f07e32926b4ae9d6e”,
“589d598f07e32926b4ae9d6f”,
“589d598f07e32926b4ae9d6d”
],
[
“589d598f07e32926b4ae9d6b”,
“589d598f07e32926b4ae9d6c”,
“589d598f07e32926b4ae9d6e”,
“589d598f07e32926b4ae9d6f”,
“589d598f07e32926b4ae9d6d”
]
]
而我只需要
[
“589d598f07e32926b4ae9d6b”,
“589d598f07e32926b4ae9d6c”,
“589d598f07e32926b4ae9d6e”,
“589d598f07e32926b4ae9d6f”,
“589d598f07e32926b4ae9d6d”
]
我就是这样做的
使用内置承诺代替蓝鸟和许多小功能:
function compileChatnameArray(company_id, paramArr) {
findOrCreateUsers(company_id, paramArr).then((userObjIdArr) => {
debug(userObjIdArr)
// here you are
})
}
/**
* @return {Promise<Array<string>>}
*/
function findOrCreateUsers(company_id, paramArr) {
const tasks = paramArr.map((paramObj) => findOrCreateUser(company_id, paramObj))
return Promise.all(tasks) // return when ALL tasks are completed
}
/**
* @param {String} _company_id
* @param {{customer_id:string, firstname:string, lastname:string}} paramObj
* @return {Promise<String>}
*/
function findOrCreateUser(_company_id, paramObj) {
const chat_name = paramObj.customer_id;
const full_name = paramObj.firstname + paramObj.lastname;
return Model.findOne({ chat_name }).then((user) => {
if (user) {
return Promise.resolve(user._id)
}
return createUser({ _company_id chat_name, full_name })
})
}
/**
* @param {{_company_id:string, chat_name:string, full_name:string}} userData
* @return {Promise<String>}
*/
function createUser(userData) {
return Model.add(userData).then((user) => Promise.resolve(user._id))
}
函数compileChatnameArray(公司id,参数){
findOrCreateUsers(公司id,参数)。然后((用户对象)=>{
调试(userObjIdArr)
//给你
})
}
/**
*@return{Promise}
*/
函数findOrCreateUsers(公司id,参数){
const tasks=paramArr.map((paramObj)=>findOrCreateUser(公司id,paramObj))
return Promise.all(tasks)//所有任务完成后返回
}
/**
*@param{String}公司id
*@param{{customer_id:string,firstname:string,lastname:string}}paramObj
*@return{Promise}
*/
函数findOrCreateUser(_company_id,paramObj){
const chat_name=paramObj.customer_id;
const full_name=paramObj.firstname+paramObj.lastname;
返回Model.findOne({chat_name})。然后((user)=>{
如果(用户){
返回承诺。解析(用户。\u id)
}
返回createUser({{公司id聊天室名称,全名})
})
}
/**
*@param{{{{u company\u id:string,chat{u name:string,full{u name:string}}userData
*@return{Promise}
*/
函数createUser(userData){
返回Model.add(userData).then((user)=>Promise.resolve(user.\u id))
}
您的映射函数不会返回任何->未定义的
返回模型。findOne({…})。lean()…
是否应该是返回模型。findOne…
在映射
函数中?@Andreas---我在这里返回:-return userObjIdArr@Manu如果我返回Model.findOne
,那么我将如何将用户添加到用户objarray
,我是否必须为此写下另一个承诺,并且我有一个检查,如果用户不在场,我将添加它并将id推送到用户objarray
。通常通过使用async
我在回调中获得userObjArray
。。。在promise.map的情况下,如何做非常困惑