Javascript Switch语句，它不适用于提示符

我刚学会了switch语句。我通过建造一些东西来练习。当我将变量的值设置为一个数字时，它会工作，但当我要求用户输入一个数字时，它总是输出默认语句

它适用于以下代码：

confirm("You want to learn basic counting?");
var i = 0;
switch (i) {
    case 0:
        console.log(i);
        i++
    case 1:
        console.log(i);
        i++;
    case 2:
        console.log(i);
        i++;
    case 3:
        console.log(i);
        i++;
    case 4:
        console.log(i);
        i++;
    case 5:
        console.log(i);
        i++;
    case 6:
        console.log(i);
        i++;
    case 7:
        console.log(i);
        i++;
    case 8:
        console.log(i);
        i++;
    case 9:
        console.log(i);
        i++;
    case 10:
        console.log(i);
        console.log("Congratulations!");
        break;
    default:
        console.log("Buzz, wronghh");
        break;
}

但当我向用户询问价值时，它并没有起作用。下面的代码不起作用：

confirm("You want to learn basic counting?");
var i = prompt("Type any number from where you want to start counting[Between 0 and 10]");
switch (i) {
    case 0:
        console.log(i);
        i++
    case 1:
        console.log(i);
        i++;
    case 2:
        console.log(i);
        i++;
    case 3:
        console.log(i);
        i++;
    case 4:
        console.log(i);
        i++;
    case 5:
        console.log(i);
        i++;
    case 6:
        console.log(i);
        i++;
    case 7:
        console.log(i);
        i++;
    case 8:
        console.log(i);
        i++;
    case 9:
        console.log(i);
        i++;
    case 10:
        console.log(i);
        console.log("Congratulations!");
        break;
    default:
        console.log("Buzz, wronghh");
        break;
}

---

您需要将用户输入从字符串转换为整数，如下所示

confirm("You want to learn basic counting?");
var i = prompt("Type any number from where you want to start counting[Between 0 and 10]");
i = parseInt(i); // this makes it an integer
switch(i) {
//...

该语句在输入表达式和大小写表达式之间执行转换。以下内容的输出为：

var i = 1;
switch (i) {
    case "1":
        console.log('String 1');
        break;
    case 1:
        console.log('Number 1');
        break;
}
// Number 1

var j = "1";
switch (j) {
    case "1":
        console.log('String 1');
        break;
    case 1:
        console.log('Number 1');
        break;
}
// String 1

prompt函数返回一个字符串，以便：

• 将案例陈述更改为

  案例“1”：

  ，

  案例“2”：

• 使用

  i=number（i）

---

谢谢！我不知道即时回答总是一个字符串。