Javascript Typescript:创建键盘事件并随时激活/停用它
我希望能够处理键盘事件,但也能够在代码中按照我的意愿停止/开始再次处理它们 我一直在阅读有关Javascript Typescript:创建键盘事件并随时激活/停用它,javascript,typescript,event-handling,dom-events,keyboard-events,Javascript,Typescript,Event Handling,Dom Events,Keyboard Events,我希望能够处理键盘事件,但也能够在代码中按照我的意愿停止/开始再次处理它们 我一直在阅读有关KeyboardEvent,以及它从Event继承的方式的文章,我发现我能够使用一些有用的方法来实现我想要实现的目标,例如: event.initEvent event.preventDefault 但经过一些研究,并试图把事情放在一起,我很挣扎,最终无法找到这样做的方法 为了证明我一直在努力找出解决方案的方法,我想向您展示我迄今为止的成果: class Game { private gameO
KeyboardEvent
,以及它从Event
继承的方式的文章,我发现我能够使用一些有用的方法来实现我想要实现的目标,例如:
event.initEvent
event.preventDefault
class Game {
private gameOver: boolean = false;
private timeOfRoundMillis: number = 5 * 1000;
private keyboardEvent: KeyboardEvent;
private capturedInput: string[];
constructor() {}
public play(): void {
this.round();
}
private round(): void {
if (!this.gameOver) {
// I want to start capturing keys
keyboardEvent.initEvent();
setTimeout(() => {
// Now I want to stop capturing keys to process the input
keyboardEvent.preventDefault();
this.processPlayerInput();
this.emptyCapturedInput();
this.round();
}, this.timeOfRoundMillis);
}
}
private processPlayerInput(): void {
// do some stuff with 'capturedInput'
}
// I want to call this every time a key is pressed if
// capturing keyboard events is active
private capture(e): void {
capturedInput.push(e.keyPressed);
}
}
可能事件是“isComposing”(布尔值,如果它正在合成,则为true)
font:经过合作,我们提出了以下解决方案:
var keypress = require('keypress');
declare var process: any;
class Game {
private gameOver: boolean = false;
private timeOfRoundMillis: number = 5 * 1000;
private capturedInput: string[];
constructor() {
keypress(process.stdin);
process.openStdin().on('keypress', (key) => {
// I want to call this every time a key is pressed
this.capturedInput.push(key);
});
process.stdin.setRawMode(true);
}
public play(): void {
this.round();
}
private round(): void {
if (!this.gameOver) {
setTimeout(() => {
// Now I want to stop capturing keys to process the input
this.isCapturingKeys = false; // need to set it to true when you desire to start capturing again
this.processPlayerInput();
this.emptyCapturedInput();
this.round();
}, this.timeOfRoundMillis);
} else {
process.stdin.pause(); // close stdin events
}
}
private processPlayerInput(): void {
// do some stuff with 'capturedInput'
}
}
这看起来不错,但我在Node.js上使用的是Typescript,所以
窗口不存在。非常感谢,你让我度过了美好的一天,它工作得非常完美!:-)为了让程序退出,我编辑了解决方案:process.stdin.pause()代码>丢失