用和替换jQuery/JavaScript中的最后一个索引

我想用

和

替换字符串中逗号（

，

）的最后一个索引

例如<代码>a、b、c与

'a、b和c'

例如

q，w，e

与

q，w和e

lastIndexOf

查找传入的参数字符串的最后一个索引

var x = 'a,b,c';
var pos = x.lastIndexOf(',');
x = x.substring(0,pos)+' and '+x.substring(pos+1);
console.log(x);

您也可以使用此功能

function replace_last_comma_with_and(x) {
    var pos = x.lastIndexOf(',');
    return x.substring(0, pos) + ' and ' + x.substring(pos + 1);
}
console.log(replace_last_comma_with_and('a,b,c,d'));

使用正则表达式的替代解决方案：

function replaceLastCommaWith(x, y) {
  return x.replace(/,(?=[^,]*$)/, " " + y + " ");
}
console.log(replaceLastCommaWith("a,b,c,d", "and")); //a,b,c and d
console.log(replaceLastCommaWith("a,b,c,d", "or")); //a,b,c or d

---

这个正则表达式应该可以完成这项工作

"a,b,c,d".replace(/(.*),(.*)$/, "$1 and $2")

试试下面的方法

var x= 'a,b,c,d';
x = x.replace(/,([^,]*)$/, " and $1");

试一试

---

一个简单的循环将帮助您解决问题

首先在字符串中使用

var str = "a,b,c,d,e";
var indices = [];
for(var i=0; i<str.length;i++) {
    if (str[i] === ",") indices.push(i);
}


indices = [1,3,5,7] as it start from 0

len = indices.length()
str[indices[len - 1]] = '.'

var str=“a、b、c、d、e”；
var指数=[]；
对于（var i=0；i
var str = "a,b,c,d,e";
var indices = [];
for(var i=0; i<str.length;i++) {
    if (str[i] === ",") indices.push(i);
}


indices = [1,3,5,7] as it start from 0

len = indices.length()
str[indices[len - 1]] = '.'