如何在Javascript中从符号、尾数和指数中获取小数

我正在尝试获取十进制/浮点的ieee754 32位表示形式。我使用此代码获取尾数、符号和指数：

function decodeIEEE64 ( value ) {

  if ( typeof value !== "number" )
    throw new TypeError( "value must be a Number" );

  var result = {
    isNegative : false,
    exponent : 0,
    mantissa : 0
  };

  if ( value === 0 ) {
    return result;
  }

  // not finite?
  if ( !isFinite( value ) ) {
    result.exponent = 2047;
    if ( isNaN( value ) ) {
      result.isNegative = false;
      result.mantissa = 2251799813685248; // QNan
    } else {
      result.isNegative = value === -Infinity;
      result.mantissa = 0;
    }
    return result;
  }

  // negative?
  if ( value < 0 ) {  result.isNegative = true;  value = -value;  }

  // calculate biased exponent
  var e = 0;
  if ( value >= Math.pow( 2, -1022 ) ) { // not denormalized
    // calculate integer part of binary logarithm
    // http://en.wikipedia.org/wiki/Binary_logarithm
    var r = value;
    while ( r < 1 ) { e -= 1; r *= 2; }
    while ( r >= 2 ) { e += 1; r /= 2; }
    e += 1023; // add bias
  }
  result.exponent = e;

  // calculate mantissa
  if ( e != 0 ) {
    var f = value / Math.pow( 2, e - 1023 );
    result.mantissa = Math.floor( (f - 1) * Math.pow( 2, 52 ) );
  } else { // denormalized
    result.mantissa = Math.floor( value / Math.pow( 2, -1074 ) );
  }

  return result;
}

var results = decodeIEEE64(0.07);
console.log(results);

所以我做了

toBinary（Math.pow（2，exponent））

和

toBinary（尾数）

现在就开始

0-100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000-1111010111000010100011110101110000100001100110011101100

这让我觉得自己做错了什么

基于此，我应该得到

0-011111011-000111110111000010001

，但我不知道从那里我会走到哪里，从二进制到十进制，没有破折号

如果有人能帮助我，我将不胜感激！谢谢

函数转换（）{
var num=parseFloat（$（“#inp”）.val（），10）；
var str=num.toString（2）；//二进制表示
console.log（num）；
//归一化并找到指数和尾数
var尾数=parseInt（str.substring（0，str.indexOf（“.”））；
var-exp=0；
控制台日志（尾数）；
如果（尾数0）{
var i=str.indexOf（“.”）；
exp=i-1；
exp=127+exp；//偏差为127；
尾数=str.replace（“.”，“”）。子串（1）；
}
返回“0”+exp.toString（2）.padStart（8，“0”）+“”+尾数；
}
$（文档）.ready（函数（）{
//$（“#结果”）.text（convert（））；
$（“#inp”）.change（函数（）{
$（“#结果”）.text（convert（））；
});
});
@OliverCharlesworth这就是我大部分代码的来源！我已经看完了所有的答案，但并没有一个给了我所有需要的。我相信我在某个地方犯了一个错误，但我没能在那篇文章中找到它。如果你看到了我忽略的东西，请告诉我！谢谢
function toBinary (decimal) {
    return decimal.toString(2);
}