JQuery/JavaScript增量数

我试图每秒递增一个给定值的数字，并使用JavaScript或JQuery保留格式

我正在努力做到这一点

假设我有这样一个数字：

1412015

每秒可以增加的数字是可变的，可以是0.1到2之间的任何值

如果每秒必须递增的值为0.54以递增数字并具有以下输出，是否可能：

1412016
1412017
1412018

谢谢

---

Eef要每秒增加一个值，请使用此结构：

var number = 0; // put your initial value here

function incrementNumber () {
    number += 1; // you can increment by anything you like here
}

// this will run incrementNumber() every second (interval is in ms)
setInterval(incrementNumber, 1000); 

这将为您设置数字格式：

function formatNumber(num) {
   num = String(num);

   if (num.length <= 3) {
      return num;
   } else {
      var last3nums = num.substring(num.length - 3, num.length);
      var remindingPart = num.substring(0, num.length - 3);
      return formatNumber(remindingPart) + ',' + last3nums;
   }
}

函数格式编号（num）{
num=字符串（num）；
如果（num.length我不太确定我是否理解您的递增情况以及您想要显示的内容。
然而，我决定加入一个格式化数字的解决方案

我有两个版本的数字格式例程，一个解析数组，另一个用正则表达式格式化。我承认它们不是最容易阅读的，但我很高兴想到了这种方法

我试着用注释来描述这些行，以防你好奇

数组解析版本：

function formatNum(num) {
    //Convert a formatted number to a normal number and split off any 
    //decimal places if they exist
    var parts = String( num ).replace(/[^\d.]-/g,'').split('.');
    //turn the string into a character array and reverse
    var arr = parts[0].split('').reverse();

    //initialize the return value
    var str = '';

    //As long as the array still has data to process (arr.length is 
    //anything but 0)
    //Use a for loop so that it keeps count of the characters for me
    for( var i = 0; arr.length; i++ ) {
        //every 4th character that isn't a minus sign add a comma before 
        //we add the character
        if( i && i%3 == 0 && arr[0] != '-' ) {
            str  = ',' + str ;
        }

        //add the character to the result
        str  = arr.shift() + str ;
    }

    //return the final result appending the previously split decimal place 
    //if necessary
    return str + ( parts[1] ? '.'+parts[1] : '' );
}

function formatNum(num) {
    //Turn a formatted number into a normal number and separate the 
    //decimal places
    var parts = String( num ).replace(/[^\d.]-/g,'').split('.');
    //reverse the string
    var str = parts[0].split('').reverse().join('');
    //initialize the return value
    var retVal = '';

    //This gets complicated. As long as the previous result of the regular 
    //expression replace is NOT the same as the current replacement, 
    //keep replacing and adding commas.
    while( retVal != (str = str.replace(/(\d{3})(\d{1,3})/,'$1,$2')) ) {
        retVal = str;
    }

    //If there were decimal points return them back with the reversed string
    if( parts[1] ) {
        return retVal.split('').reverse().join('') + '.' + parts[1];
    }

    //return the reversed string
    return retVal.split('').reverse().join('');
}

var num = 1412015;

setInterval(function(){
    //Your 0.54 value... why? I don't know... but I'll run with it.
    num += 0.54;
    console.log( formatNum( num ) );
},1000);

正则表达式版本：

function formatNum(num) {
    //Convert a formatted number to a normal number and split off any 
    //decimal places if they exist
    var parts = String( num ).replace(/[^\d.]-/g,'').split('.');
    //turn the string into a character array and reverse
    var arr = parts[0].split('').reverse();

    //initialize the return value
    var str = '';

    //As long as the array still has data to process (arr.length is 
    //anything but 0)
    //Use a for loop so that it keeps count of the characters for me
    for( var i = 0; arr.length; i++ ) {
        //every 4th character that isn't a minus sign add a comma before 
        //we add the character
        if( i && i%3 == 0 && arr[0] != '-' ) {
            str  = ',' + str ;
        }

        //add the character to the result
        str  = arr.shift() + str ;
    }

    //return the final result appending the previously split decimal place 
    //if necessary
    return str + ( parts[1] ? '.'+parts[1] : '' );
}

function formatNum(num) {
    //Turn a formatted number into a normal number and separate the 
    //decimal places
    var parts = String( num ).replace(/[^\d.]-/g,'').split('.');
    //reverse the string
    var str = parts[0].split('').reverse().join('');
    //initialize the return value
    var retVal = '';

    //This gets complicated. As long as the previous result of the regular 
    //expression replace is NOT the same as the current replacement, 
    //keep replacing and adding commas.
    while( retVal != (str = str.replace(/(\d{3})(\d{1,3})/,'$1,$2')) ) {
        retVal = str;
    }

    //If there were decimal points return them back with the reversed string
    if( parts[1] ) {
        return retVal.split('').reverse().join('') + '.' + parts[1];
    }

    //return the reversed string
    return retVal.split('').reverse().join('');
}

var num = 1412015;

setInterval(function(){
    //Your 0.54 value... why? I don't know... but I'll run with it.
    num += 0.54;
    console.log( formatNum( num ) );
},1000);

假设您希望每秒输出一个格式化的数字，递增0.54，您可以使用一个间隔来进行递增和输出

只有Firebug的超短Firefox示例：

function formatNum(num) {
    //Convert a formatted number to a normal number and split off any 
    //decimal places if they exist
    var parts = String( num ).replace(/[^\d.]-/g,'').split('.');
    //turn the string into a character array and reverse
    var arr = parts[0].split('').reverse();

    //initialize the return value
    var str = '';

    //As long as the array still has data to process (arr.length is 
    //anything but 0)
    //Use a for loop so that it keeps count of the characters for me
    for( var i = 0; arr.length; i++ ) {
        //every 4th character that isn't a minus sign add a comma before 
        //we add the character
        if( i && i%3 == 0 && arr[0] != '-' ) {
            str  = ',' + str ;
        }

        //add the character to the result
        str  = arr.shift() + str ;
    }

    //return the final result appending the previously split decimal place 
    //if necessary
    return str + ( parts[1] ? '.'+parts[1] : '' );
}

function formatNum(num) {
    //Turn a formatted number into a normal number and separate the 
    //decimal places
    var parts = String( num ).replace(/[^\d.]-/g,'').split('.');
    //reverse the string
    var str = parts[0].split('').reverse().join('');
    //initialize the return value
    var retVal = '';

    //This gets complicated. As long as the previous result of the regular 
    //expression replace is NOT the same as the current replacement, 
    //keep replacing and adding commas.
    while( retVal != (str = str.replace(/(\d{3})(\d{1,3})/,'$1,$2')) ) {
        retVal = str;
    }

    //If there were decimal points return them back with the reversed string
    if( parts[1] ) {
        return retVal.split('').reverse().join('') + '.' + parts[1];
    }

    //return the reversed string
    return retVal.split('').reverse().join('');
}

var num = 1412015;

setInterval(function(){
    //Your 0.54 value... why? I don't know... but I'll run with it.
    num += 0.54;
    console.log( formatNum( num ) );
},1000);

您可以在这里看到所有这些操作：
谢谢，我不太懂javascript，是否也可以将数字格式化为1412016？您的代码只适用于大于6的数字。如果他想要1548怎么办？