Javascript 如何使用firebase/vue.js实时生成删除函数
它成功地工作了,但我不知道如何使它与Firestore实时。我只知道当我添加一些东西时如何使其实时,正如您在下面的代码中看到的:Javascript 如何使用firebase/vue.js实时生成删除函数,javascript,firebase,vue.js,google-cloud-firestore,vuetify.js,Javascript,Firebase,Vue.js,Google Cloud Firestore,Vuetify.js,它成功地工作了,但我不知道如何使它与Firestore实时。我只知道当我添加一些东西时如何使其实时,正如您在下面的代码中看到的: removeData(doc) { if (confirm("Are you sure ?")) { db.collection("projects") .doc(doc) .delete() .then(() => { console.log("D
removeData(doc) {
if (confirm("Are you sure ?")) {
db.collection("projects")
.doc(doc)
.delete()
.then(() => {
console.log("Document successfully deleted!");
});
}
},
如果
this.projects
是一个数组,则可以使用以下方法从中删除删除项:
created() {
db.collection("projects").onSnapshot((res) => {
const changes = res.docChanges();
changes.forEach((change) => {
if (change.type === "added") {
this.projects.push({
...change.doc.data(),
id: change.doc.id,
});
}
if (change.type === "removed") {
//code goes here
}
});
});
},
另请参阅上的MDN文档
created() {
db.collection("projects").onSnapshot((res) => {
const changes = res.docChanges();
changes.forEach((change) => {
if (change.type === "added") {
this.projects.push({
...change.doc.data(),
id: change.doc.id,
});
}
if (change.type === "removed") {
//code goes here
}
});
});
},
if (change.type === "removed") {
this.projects = this.projects.filter(item => item.id !== change.doc.id);
}