Javascript-XML加载jQuery

我在使用jQuery将XML数据加载到javascript时遇到问题

我这里有一个xml：

<config>
<device>
    <node>1</node>
    <name>Block</name>
    <description>Block in saloon</description>
    <area>Salon</area>
</device>   
<device>
    <node>2</node>
    <name>Line</name>
    <description>Lottr</description>
    <area>Living room</area>
</device>   
</config>   

---

我应该在var kurs里放什么

类似于这个问题：

var myVal;
$(xml).find('node').each(  //find the node and loop through them
    function(){
        var node = $(this);  
        if (node.text==="2") {   //see if the node's value is 2
            myVal = node.siblings("name").text();  //find the sibling name element
            return false;  //exit the each loop
        }
    }
);
console.log(myVal);

我认为这样做应该奏效：

$.ajax({
     type: "GET",
     url: "config2.xml",
     dataType: "xml",
     success: function(xml) {
        //this should get you the device node 
        var $kurs = $(xml).find('node:contains("2")').parent();
        //this should get you the name from the device node
        var name = $kurs.find('name'); 
     }
}); 

---

})

我不明白你的问题。你想在库尔人身上放什么？为什么？到底是什么问题？正在加载文件吗？

$.ajax({
     type: "GET",
     url: "config2.xml",
     dataType: "xml",
     success: function(xml) {
        //this should get you the device node 
        var $kurs = $(xml).find('node:contains("2")').parent();
        //this should get you the name from the device node
        var name = $kurs.find('name'); 
     }
}); 

$(document).ready(function () {

  $.ajax({
    type: "GET",
    url: "config2.xml",
    dataType: "xml",
    success: function (xml) {
      $(xml).find('device').each(function () {
        var node = $(this).find('node');

        if (node.text() == '2') {
          name = $(this).find('name').text();
        }

      });
    }
  });