在Javascript中合并两个对象

我有两个JSON，我想在Javascript中添加两个JSON（将JSOB对象加入JSON A）

JSON A:-

{

    "data": [{
        "id": 1,
        "subgroup": "1",
        "power": "2",
        "grp": "1"
    }, {
        "id": 1,
        "subgroup": "1",
        "power": "1",
        "grp": "1"
    }, {
        "id": 2,
        "subgroup": "1",
        "power": "1",
        "grp": "2"
    }, {
        "id": 3,
        "subgroup": "2",
        "power": "1",
        "grp": "2"
    }, {
        "id": 4,
        "subgroup": "1",
        "power": "1",
        "grp": "3"
    }, {
        "id": 5,
        "subgroup": "2",
        "power": "1",
        "grp": "2"
    }, {
        "id": 6,
        "subgroup": "2",
        "power": "1",
        "grp": "1"
    }, {
        "id": 7,
        "subgroup": "1",
        "power": "1",
        "grp": "4"
    }, {
        "id": 1,
        "subgroup": "3",
        "power": "2",
        "grp": "4"
    }

}

JSON B:-

{

    "data": [{
        "id": 1,
        "subgroup": "3",
        "power": "2",
        "grp": "4"
    }, {
        "id": 1,
        "subgroup": "4",
        "power": "1",
        "grp": "3"
    }

}

JSON A和JSON B中的键名称相似。我们可以看到，

subgroup3

和

subgroup4

分别出现在

GRP4

和

GRP3

中（查看JSON B）。我想将JSON B中的每个

子组

添加到JSON A中的每个

grp

（除了那些

grp

s子组s已经存在的

s。就像JSON A中有一个带有
subgroup3
和
grp4
的条目，我们将跳过）。
Id
，
power
的值将分别相似。因此，我们希望在
grp 1,2,3中添加
子组3
，并在
组1,2,4中添加
子组4
。对于
子组3
，
power
和
id
值分别为
2,1
，对于
子组4
，
power
和
id
值分别为
1,1

输出的最终JSON应该是

{

    "data": [{
        "id": 1,
        "subgroup": "1",
        "power": "2",
        "grp": "1"
    }, {
        "id": 1,
        "subgroup": "1",
        "power": "1",
        "grp": "1"
    }, {
        "id": 2,
        "subgroup": "1",
        "power": "1",
        "grp": "2"
    }, {
        "id": 3,
        "subgroup": "2",
        "power": "1",
        "grp": "2"
    }, {
        "id": 4,
        "subgroup": "1",
        "power": "1",
        "grp": "3"
    }, {
        "id": 5,
        "subgroup": "2",
        "power": "1",
        "grp": "2"
    }, {
        "id": 6,
        "subgroup": "2",
        "power": "1",
        "grp": "1"
    }, {
        "id": 7,
        "subgroup": "1",
        "power": "1",
        "grp": "4"
    }, {
        "id": 1,
        "subgroup": "3",
        "power": "2",
        "grp": "4"
    }, {
        "id": 1,
        "subgroup": "3",
        "power": "2",
        "grp": "1"
    }, {
        "id": 1,
        "subgroup": "3",
        "power": "2",
        "grp": "2"
    }, {
        "id": 1,
        "subgroup": "3",
        "power": "2",
        "grp": "3"
    }, {
        "id": 1,
        "subgroup": "4",
        "power": "1",
        "grp": "1"
    }, {
        "id": 1,
        "subgroup": "4",
        "power": "1",
        "grp": "2"
    }, {
        "id": 1,
        "subgroup": "4",
        "power": "1",
        "grp": "4"
    }

}

我可以将对象添加到JSON中

var myObj = {
        "id" : id,
        "subgroup" : subgroup,
        "power" : power,
        "grp" : grp

}

从JSON B加入JSON A并跳过
子组
已存在于
grp
JSON中的条目的推荐方法是什么

可以像这样合并对象

ECMAScript 2015（ES6）标准方法

/* For the case in question, you would do: */
Object.assign(obj1, obj2);

/** There's no limit to the number of objects you can merge.
 *  All objects get merged into the first object. 
 *  Only the object in the first argument is mutated and returned.
 *  Later properties overwrite earlier properties with the same name. */
const allRules = Object.assign({}, obj1, obj2, obj3, etc);

有关详细说明，请参见

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