Javascript jquery post调用不使用url末尾的斜杠

示例url:
目标不是显示.php扩展名，而是当页面/url以斜杠结尾打开时，内容停止工作
-表单正在使用此url
-表单无法使用此url

文件夹和文件：
|
|/js/custom.js
|/manager/create.php
|/manager/creategetpostdata.php
|/manager/.htaccess

custom.js上的内容

$(window).load(function() {
    // get post code data
    $('.contentfinder').on('keyup', function(e){
        var xyz = $(this).closest('.contentRow');
        //alert( "success" );
        $.post("../manager/creategetpostdata.php", xyz.find('.contentfinder').serialize(),  function(response) {
            //alert( "success" );
            xyz.children('.showPostData').html(response);
            xyz.children('.showPostData').show();
        });

    });

});

在create.php文件上输入表单：

                    <div class="contentRow">
                        <input type="text" name="inputdata" class="form-control contentfinder" placeholder="" />
                        <div class="showPostData"></div>
                    </div>

有什么帮助吗？ 提前谢谢

| | | | | | | | | | | |

    var loc = window.location.pathname;
    var dir = loc.substring(0, loc.lastIndexOf('/create'));

        $.post( dir + "/creategetpostdata.php", xyz.find('.contentfinder').serialize(),  function(response) {
            //alert( "success" );
            xyz.children('.showPostData').html(response);
            xyz.children('.showPostData').show();
        });

---

这可能与此相关：@JeremyThille感谢您的帮助。：）

Options +FollowSymLinks -MultiViews
RewriteEngine On

RewriteCond %{THE_REQUEST} \s/+(.+?)\.php\?([^=]+)=([^\s&]+) [NC]
RewriteRule ^ /%1/%2/%3? [R=302,L,NE]

RewriteCond %{THE_REQUEST} \s/+(.+?)\.php\s [NC]
RewriteRule ^ /%1 [R=302,L,NE]

RewriteCond %{REQUEST_FILENAME} -f [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^ - [L]

RewriteCond %{REQUEST_FILENAME}.php -f
RewriteRule ^(.+?)/?$ $1.php [L]

    var loc = window.location.pathname;
    var dir = loc.substring(0, loc.lastIndexOf('/create'));

        $.post( dir + "/creategetpostdata.php", xyz.find('.contentfinder').serialize(),  function(response) {
            //alert( "success" );
            xyz.children('.showPostData').html(response);
            xyz.children('.showPostData').show();
        });