Javascript 基于某个常量值的Angular js filter下拉选项

如何从Json对象下方列出下拉选项，其中

IsDeleted==0

"currencies":[{
    "CurrencyID":"1",
    "CurrencyCode":"AED",
    "CurrencyName":"United Arab Emirates Dirham",
    "IsDeleted":"1"
},{
    "CurrencyID":"2",
    "CurrencyCode":"AFN",
    "CurrencyName":"Afghan Afghani",
    "IsDeleted":"1"
},{
    "CurrencyID":"3",
    "CurrencyCode":"ALL",
    "CurrencyName":"Albanian Lek",
    "IsDeleted":"1"
}];


<select ng-model="data.CurrencyID" ng-options="cu.CurrencyID as cu.CurrencyName for cu in currencies | filter : IsDeleted :'0'"></select>

“货币”：[{
“CurrencyID”：“1”，
“货币代码”：“AED”，
“CurrencyName”：“阿拉伯联合酋长国迪拉姆”，
“已删除”：“1”
},{
“CurrencyID”：“2”，
“货币代码”：“AFN”，
“CurrencyName”：“阿富汗阿富汗人”，
“已删除”：“1”
},{
“CurrencyID”：“3”，
“CurrencyCode”：“全部”，
“CurrencyName”：“阿尔巴尼亚列克”，
“已删除”：“1”
}];

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在IsDeleted中：“0”只需在IsDeleted之后替换“：”by“=”运算符

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实际上，问题在于将默认值分配给货币$scope.currences={}；它抛出错误，过滤器停止工作。。每当在json数组上使用过滤器时，默认值不应为$scope.currences={}；

<select ng-model="data.CurrencyID" ng-options="cu.CurrencyID as cu.CurrencyName for cu in currencies |filter : {IsDeleted :'0'}"></select>