Javascript 按用户定义的角度旋转图像画布
我想旋转一个用户定义的角度,这将是由一个输入滑块,范围从-90度到90度来确定的图像。基本上,要求是拉直画布上的图像 这就是我使用angularjs所尝试的 我的输入滑块和html:Javascript 按用户定义的角度旋转图像画布,javascript,jquery,angularjs,html,canvas,Javascript,Jquery,Angularjs,Html,Canvas,我想旋转一个用户定义的角度,这将是由一个输入滑块,范围从-90度到90度来确定的图像。基本上,要求是拉直画布上的图像 这就是我使用angularjs所尝试的 我的输入滑块和html: Straighten: <input type="range" id="rotateImage" value="0" min="-90" max="90" step="1" ng-model="rotateAngle"/> <div id="imageCanvas"> <can
Straighten: <input type="range" id="rotateImage" value="0" min="-90" max="90" step="1" ng-model="rotateAngle"/>
<div id="imageCanvas">
<canvas id="canvas"></canvas>
</div>
我还在画布上画了一个网格作为参考
$scope.Straighten = function() {
var imageCanvas = document.getElementById("canvas"),
gridWidth = imageCanvas.width,
canvasWidth = gridWidth,
gridHeight = imageCanvas.height,
canvasHeight = gridHeight,
gridPadding = 1;
var gridCanvas = $('<canvas id=gridLayer></canvas>').attr({
width: canvasWidth,
height: canvasHeight
}).appendTo('#imageCanvas');
var context = gridCanvas.get(0).getContext("2d");
drawGridBoard(gridWidth, gridHeight, gridPadding, context);
}
function drawGridBoard(gridWidth, gridHeight, gridPadding, context) {
for (var x = 0; x <= gridWidth; x += 40) {
context.moveTo(0.5 + x + gridPadding, gridPadding);
context.lineTo(0.5 + x + gridPadding, gridHeight + gridPadding);
}
for (var x = 0; x <= gridHeight; x += 40) {
context.moveTo(gridPadding, 0.5 + x + gridPadding);
context.lineTo(gridWidth + gridPadding, 0.5 + x + gridPadding);
}
context.strokeStyle = "blue";
context.setLineDash([15, 5]);
context.stroke();
$scope.right=function(){
var imageCanvas=document.getElementById(“画布”),
gridWidth=imageCanvas.width,
画布宽度=网格宽度,
gridHeight=imageCanvas.height,
画布高度=网格高度,
网格填充=1;
var gridCanvas=$('').attr({
宽度:画布宽度,
高度:画布高度
}).appendTo(“#imageCanvas”);
var context=gridCanvas.get(0.getContext(“2d”);
drawGridBoard(网格宽度、网格高度、网格填充、上下文);
}
函数drawGridBoard(gridWidth、gridHeight、gridPadding、context){
对于(var x=0;x我已经在画布上工作了两周。我正在更新你的旋转函数。也许你应该等到图像加载后再绘制。请发布下面的代码
function rotate(rotAngle) {
console.log('rotate angle>> ', rotAngle);
var canvas= document.getElementById("canvas"),
context = canvas.getContext("2d");
context.clearRect(0, 0, canvas.width, canvas.height); //Clear the canvas first
var logoImg = new Image(); // Create instance of the Image class
logoImg.src = item.image; // Tell the Image's relative url
var gridWidth = canvas.width,
var gridHeight = canvas.height;
var deg = Math.PI / 180;
logoImg.onload = function () {
context.save();
context.translate(gridWidth / 2, gridHeight / 2);
context.rotate(rotAngle * Math.PI / 180);
context.drawImage(logoImg, -(gridWidth / 2), -(gridHeight / 2));
context.restore();
};
}
以上代码对我很有用。非常感谢:)它工作得很好。但我现在唯一的问题是。漫游时我们会得到额外的空间。我如何通过缩放图像来填充空间并能够平移图像来填充空间?如果你看到我的答案足够好,请不要忘了向上投票。对于你的下一个查询,请你创建一个小提琴,这样我就可以看到我自己了吗?
function rotate(rotAngle) {
console.log('rotate angle>> ', rotAngle);
var canvas= document.getElementById("canvas"),
context = canvas.getContext("2d");
context.clearRect(0, 0, canvas.width, canvas.height); //Clear the canvas first
var logoImg = new Image(); // Create instance of the Image class
logoImg.src = item.image; // Tell the Image's relative url
var gridWidth = canvas.width,
var gridHeight = canvas.height;
var deg = Math.PI / 180;
logoImg.onload = function () {
context.save();
context.translate(gridWidth / 2, gridHeight / 2);
context.rotate(rotAngle * Math.PI / 180);
context.drawImage(logoImg, -(gridWidth / 2), -(gridHeight / 2));
context.restore();
};
}