I';我试图生成一个数组,但是相同的id标记破坏了html-javascript
我一整天都在为此而挣扎。在我学习如何使这个动态之前,我想用不同的id标记或类名而不是id生成多个div。哪一个容易。目前我有一个问题,我的页面吐出一个数组,其中每个div都有相同的id。请告知I';我试图生成一个数组,但是相同的id标记破坏了html-javascript,javascript,html,arrays,json,Javascript,Html,Arrays,Json,我一整天都在为此而挣扎。在我学习如何使这个动态之前,我想用不同的id标记或类名而不是id生成多个div。哪一个容易。目前我有一个问题,我的页面吐出一个数组,其中每个div都有相同的id。请告知 function byId(id) { return document.getElementById(id); } var txt = { "characters": [{ "thumbn": "<img src=\"http:\/\/galnova.com
function byId(id) {
return document.getElementById(id);
}
var txt = {
"characters": [{
"thumbn": "<img src=\"http:\/\/galnova.com\/nu_images\/tiled.jpg\"\/>",
"fullName": "John Doe",
"speci": "human male",
"occup": "Web Personality",
"cide": "Sleeper",
"descr": "blah",
"biog": "blarg",
"allia": "chaos good",
"fullon": "<img src=\"http:\/\/galnova.com\/nu_images\/ban_two.jpg\"\/>"
},
{
"thumbn": "<img src=\"http://galnova.com/nu_images/tiled.jpg\"/>",
"fullName": "Jane Doe",
"speci": "human female",
"occup": "Movie Producer",
"cide": "Citric",
"descr": "bluh",
"biog": "blurg",
"allia": "neutral",
"fullon": "<img src=\"http:\/\/galnova.com\/nu_images\/tiled.jpg\"\/>"
},
{
"thumbn": "<img src=\"http://galnova.com/nu_images/tiled.jpg\"/>",
"fullName": "Canter Doma",
"speci": "alienmale",
"occup": "Chef",
"cide": "Galv",
"descr": "bleh",
"biog": "blerg",
"allia": "evil",
"fullon": "<img src=\"http:\/\/galnova.com\/nu_images\/tiled.jpg\"\/>"
}]
};
var obj = txt;
//obj.toString();
byId("thumb").innerHTML = obj.characters[0,1,2].thumbn;
byId("fname").innerHTML = obj.characters[0,1,2].fullName;
byId("spec").innerHTML = obj.characters[0,1,2].speci;
byId("occu").innerHTML = obj.characters[0,1,2].occup;
byId("cid").innerHTML = obj.characters[0,1,2].cide;
byId("desc").innerHTML = obj.characters[0,1,2].descr;
byId("bio").innerHTML = obj.characters[0,1,2].biog;
byId("alli").innerHTML = obj.characters[0,1,2].allia;
byId("char").innerHTML = obj.characters[0,1,2].fullon;
函数byId(id){
返回文档.getElementById(id);
}
var txt={
“字符”:[{
“拇指”:“,
“全名”:“约翰·多伊”,
“speci”:“人类男性”,
“占领者”:“网络人格”,
“犯罪现场”:“睡眠者”,
“描述”:“废话”,
“传记”:“布拉格”,
“allia”:“混沌好”,
“富隆”:”
},
{
“拇指”:“,
“全名”:“无名氏”,
“speci”:“人类女性”,
“占领者”:“电影制片人”,
“谋杀”:“柠檬”,
“描述”:“蓝色”,
“传记”:“模糊”,
“allia”:“中立”,
“富隆”:”
},
{
“拇指”:“,
“全名”:“Canter Doma”,
“speci”:“alienmale”,
“占领者”:“厨师”,
“谋杀”:“Galv”,
“描述”:“bleh”,
“传记”:“blerg”,
“allia”:“邪恶”,
“富隆”:”
}]
};
var obj=txt;
//对象toString();
byId(“thumb”).innerHTML=obj.characters[0,1,2].thumbn;
byId(“fname”).innerHTML=obj.characters[0,1,2]。全名;
byId(“spec”).innerHTML=obj.characters[0,1,2].speci;
byId(“ocu”).innerHTML=obj.characters[0,1,2].ocup;
byId(“cid”).innerHTML=obj.characters[0,1,2].cide;
byId(“desc”).innerHTML=obj.characters[0,1,2].descr;
byId(“bio”).innerHTML=obj.characters[0,1,2].biog;
byId(“alli”).innerHTML=obj.characters[0,1,2].allia;
byId(“char”).innerHTML=obj.characters[0,1,2].fullon;
您的阵列不是这样工作的 您拥有的结构是
{[{},{},{}]}
,这意味着
object{array[object{},object{},object{}]}
使用json和javascript并不能简单地实现您编写的内容
相反,尝试
// John Doe
byId("thumb").innerHTML = obj.characters[0].thumbn;
byId("fname").innerHTML = obj.characters[0].fullName;
byId("spec").innerHTML = obj.characters[0].speci;
byId("occu").innerHTML = obj.characters[0].occup;
byId("cid").innerHTML = obj.characters[0].cide;
byId("desc").innerHTML = obj.characters[0].descr;
byId("bio").innerHTML = obj.characters[0].biog;
byId("alli").innerHTML = obj.characters[0].allia;
byId("char").innerHTML = obj.characters[0].fullon;
下一个是1
// Jane Doe
byId("thumb").innerHTML = obj.characters[1].thumbn;
byId("fname").innerHTML = obj.characters[1].fullName;
byId("spec").innerHTML = obj.characters[1].speci;
byId("occu").innerHTML = obj.characters[1].occup;
byId("cid").innerHTML = obj.characters[1].cide;
byId("desc").innerHTML = obj.characters[1].descr;
byId("bio").innerHTML = obj.characters[1].biog;
byId("alli").innerHTML = obj.characters[1].allia;
byId("char").innerHTML = obj.characters[1].fullon;
==编辑==
为了更好地满足您的需求,基于评论,这可能就足够了
将对象封装在文本中,并构建在文本中过滤或构建html所需的函数中
var obj = {
txt: {
"characters": [{
"thumbn": "<img src=\"http:\/\/galnova.com\/nu_images\/tiled.jpg\"\/>",
"fullName": "John Doe",
"speci": "human male",
"occup": "Web Personality",
"cide": "Sleeper",
"descr": "blah",
"biog": "blarg",
"allia": "chaos good",
"fullon": "<img src=\"http:\/\/galnova.com\/nu_images\/ban_two.jpg\"\/>"
},
{
"thumbn": "<img src=\"http://galnova.com/nu_images/tiled.jpg\"/>",
"fullName": "Jane Doe",
"speci": "human female",
"occup": "Movie Producer",
"cide": "Citric",
"descr": "bluh",
"biog": "blurg",
"allia": "neutral",
"fullon": "<img src=\"http:\/\/galnova.com\/nu_images\/tiled.jpg\"\/>"
},
{
"thumbn": "<img src=\"http://galnova.com/nu_images/tiled.jpg\"/>",
"fullName": "Canter Doma",
"speci": "alienmale",
"occup": "Chef",
"cide": "Galv",
"descr": "bleh",
"biog": "blerg",
"allia": "evil",
"fullon": "<img src=\"http:\/\/galnova.com\/nu_images\/tiled.jpg\"\/>"
}]
},
byId: function(id) {
return document.getElementById(id);
},
buildHtml: function(id) {
this.byId("thumb").innerHTML = this.txt.characters[id].thumbn;
this.byId("fname").innerHTML = this.txt.characters[id].fullName;
this.byId("spec").innerHTML = this.txt.characters[id].speci;
this.byId("occu").innerHTML = this.txt.characters[id].occup;
this.byId("cid").innerHTML = this.txt.characters[id].cide;
this.byId("desc").innerHTML = this.txt.characters[id].descr;
this.byId("bio").innerHTML = this.txt.characters[id].biog;
this.byId("alli").innerHTML = this.txt.characters[id].allia;
this.byId("char").innerHTML = this.txt.characters[id].fullon;
}
};
不是100%确定要执行的操作,但是快速浏览一下,您可能没有按照预期引用字符数组:
obj.characters[0,1,2].thumbn;
将始终为您提供数组中的第三项,因为您使用,
(逗号)运算符在这种情况下将始终导致传递为2
的值
如果需要项目1、obj.字符[0]
、项目2obj.字符[1]
,等等
为了扩展,javascript中一系列逗号的返回值将是最后一次求值。例如:('a',1020,'dog')
将计算为'dog'<代码>(10,20,30)=30//true
看了看小提琴,我还是有点不清楚问题是什么/你想做什么。我没有看到任何重复的ID。您是在尝试创建多张卡片,每个角色一张,还是尝试使用一张卡片和另一个角色的统计数据替换其内容,或者其他什么?我希望所有对象都以html生成,而不仅仅是数组中的最后一张。我刚刚意识到我把事情搞砸了,但我不知道如何解决它。html是静态的,无论数组中有多少对象,我每次都需要以某种方式生成具有唯一id的块!我真的很想找到一种更干净的方法,通过I++的东西将每个数组传递给一个空的数组,但我正在和术语作斗争。我认为一次显示一个字符是可以的…我只是想创建一种方式,在其中切换。我不能以某种方式滚动每个字符[]吗?请参阅使用文字更新,如果要滚动字符,请使用for循环,您可以使用foreach,但它是ECMAScript 5,并不总是与所有浏览器兼容。你能不能给我看看所有能用的东西。如果我不明白的话。对不起,我的byId函数坏了,我现在已经修好了。你能再试一次吗?
obj.characters[0,1,2].thumbn;