Jquery 完全重新格式化json响应

我有一个.json响应，需要将其重新格式化为不同的响应，最终我将重新分析并保存该响应，以便在其他地方的代码的不同部分中使用

我不完全确定如何描述我在这里所做的工作，但在我知道我的数组以正确的格式分组后，我可以解析json：-\

请允许我向您展示代码，以及输出应该是什么样子：

{"response": {"docs":[ { "set_number":"1","set_description":"first description", "subsets":[ {"subset_number":"845","subset_description 2":"hello 3"}, {"subset_number":"835","subset_description 1":"hello 2"} ] }, { "set_number":"2","set_description":"first description", "subsets":[ {"subset_number":"855","subset_description 3":"hello 4"}, {"subset_number":"865","subset_description 4":"hello 5"} }, { "set_number":"3","set_description":"first description", "subsets":[ {"subset_number":"875","subset_description 5":"hello 6"} ] }, { "set_number":"4","set_description":"first description", "subsets":[ {"subset_number":"895","subset_description 7":"hello 8"}, {"subset_number":"885","subset_description 6":"hello 7"} [ }, ] } } 当前json格式：

{"response": {"docs":[ {"set_number":"1","set_description":"first description","subset_number":"835","subset_description 1":"hello 2" }, {"set_number":"1","set_description":"first description","subset_number":"845","subset_description 2":"hello 3" }, {"set_number":"2","set_description":"first description","subset_number":"855","subset_description 3":"hello 4" }, {"set_number":"2","set_description":"first description","subset_number":"865","subset_description 4":"hello 5" }, {"set_number":"3","set_description":"first description","subset_number":"875","subset_description 5":"hello 6" }, {"set_number":"4","set_description":"first description","subset_number":"885","subset_description 6":"hello 7" }, {"set_number":"4","set_description":"first description","subset_number":"895","subset_description 7":"hello 8" }, ] } } {“答复”： {“文件”：[ {“集合描述号”：“1”，“集合描述号”：“第一描述”，“子集描述号”：“835”，“子集描述号1”：“你好2”}， {“集合描述编号”：“1”，“集合描述”：“第一描述”，“子集描述编号”：“845”，“子集描述2”：“你好3”}， {“集合描述编号”：“2”，“集合描述”：“第一描述”，“子集描述编号”：“855”，“子集描述3”：“你好4”}， {“集合描述编号”：“2”，“集合描述”：“第一描述”，“子集描述编号”：“865”，“子集描述4”：“hello 5”}， {“集合号”：“3”，“集合号说明”：“第一个说明”，“子集号”：“875”，“子集号说明5”：“你好6”}， {“集合描述编号”：“4”，“集合描述”：“第一描述”，“子集描述编号”：“885”，“子集描述6”：“你好7”}， {“集合编号”：“4”，“集合描述”：“第一描述”，“子集编号”：“895”，“子集描述7”：“你好8”}， ] } } 。。下面是我试图让它看起来像：

{"response": {"docs":[ { "set_number":"1","set_description":"first description", "subsets":[ {"subset_number":"845","subset_description 2":"hello 3"}, {"subset_number":"835","subset_description 1":"hello 2"} ] }, { "set_number":"2","set_description":"first description", "subsets":[ {"subset_number":"855","subset_description 3":"hello 4"}, {"subset_number":"865","subset_description 4":"hello 5"} }, { "set_number":"3","set_description":"first description", "subsets":[ {"subset_number":"875","subset_description 5":"hello 6"} ] }, { "set_number":"4","set_description":"first description", "subsets":[ {"subset_number":"895","subset_description 7":"hello 8"}, {"subset_number":"885","subset_description 6":"hello 7"} [ }, ] } } {“答复”： {“文件”：[ { “集合编号”：“1”，“集合描述”：“第一描述”， “子集”：[ {“子集编号”：“845”，“子集描述2”：“hello 3”}， {“子集编号”：“835”，“子集描述1”：“你好2”} ] }, { “集合编号”：“2”，“集合描述”：“第一描述”， “子集”：[ {“子集编号”：“855”，“子集描述3”：“hello 4”}， {“子集编号”：“865”，“子集描述4”：“hello 5”} }, { “集合编号”：“3”，“集合描述”：“第一描述”， “子集”：[ {“子集编号”：“875”，“子集描述5”：“你好6”} ] }, { “集合编号”：“4”，“集合描述”：“第一描述”， “子集”：[ {“子集编号”：“895”，“子集描述7”：“hello 8”}， {“子集编号”：“885”，“子集描述6”：“你好7”} [ }, ] } } 如您所见，我基本上组合了所有子集信息，因此响应更清晰，并分组在一起

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非常感谢您提供的任何帮助！

以下内容可以满足您的要求：

function reformat(input) {
    // We'll update this as we progress through the input array
    var output = {
        docs: []
    }

    // We use this as a handy, reusable way to either find an existing
    // setNumber, or create a placeholder for it and return the new one
    // if none existed
    function find(setNumber, setDescription) {
        var docs = output.docs;

        // Try and find an existing entry which has the same set number
        // as we're looking for
        for (var i=0;i<docs.length;i++) {
            if (docs[i]["set_number"] == setNumber) {
                return docs[i];
            };
        };

        // If we get this far, none exist; so create and add to the array here
        var newOne = {
            'set_number': setNumber,
            'set_description' : setDescription,
            subsets: []
        };

        docs.push(newOne);

        return newOne;
    };

    // Heres the actual work; loop through the input array, use `find` to
    // find or create the entry in the output array, and add the current
    // subset to its list
    for (var i=0;i<input.docs.length;i++) {
        var doc = input.docs[i];
        var current = find(doc["set_number"], doc["set_description"]);

        current.subsets.push({
            'subset_number': docs["subset_number"],
            'subset_description': docs["subset_description"]
        });
    }

    return output;
}

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你想用JavaScript还是怎么做？