Jquery 如何按顺序设置位置动画?
我想按顺序移动拼图块,而不是立即移动 下面是我的脚本:Jquery 如何按顺序设置位置动画?,jquery,asp.net-mvc,Jquery,Asp.net Mvc,我想按顺序移动拼图块,而不是立即移动 下面是我的脚本: $(document).ready(function () { $("#left").click(function () { for (var i = 1; i < length; i++) { var string = "#s" + i.toString(); $(string).animate({ "left": "+=50px
$(document).ready(function () {
$("#left").click(function () {
for (var i = 1; i < length; i++) {
var string = "#s" + i.toString();
$(string).animate({ "left": "+=50px" }, "slow");
}
});
$(文档).ready(函数(){
$(“#左”)。单击(函数(){
对于(变量i=1;i
有了这个代码,所有的瓷砖都会一次向左移动,但我想按顺序移动瓷砖
例如:向左移动#s1,2秒后向上移动#s2并继续
注意,我的动作是可变的
对不起,我的英语不好!这可以通过使用
来实现。each()
方法,给所有的tile指定一个类名,并执行类似的操作
$(document).ready(function () {
$("#left").click(function () {
$('.tiles').each(function() {
$(this).animate({ "left": "+=50px" }, "slow");
});
});
});
您可以将方法和函数结合使用,如下所示: 在这里拉小提琴: 示例HTML
<div id="#left">
<div class="tile"></div>
<div class="tile"></div>
<div class="tile"></div>
<div class="tile"></div>
</div>
jQuery代码
function anim($target){
$target.animate({'left' : '+=50px'}, 'slow');
}
$('.tile').each(function(index, el){
var $target = $(this);
setTimeout(function(){anim($target)}, (1000 * index)); // Change 1000 to +/- delay
});
我希望这有帮助!您的问题让我感兴趣,因此我在JSFIDLE上提供了一个快速示例: 基本思想是使用jQuery
.animate()函数的回调函数来迭代要设置动画的DOM元素列表
//first I'm setting up the variables I'll need
var $items = [$('#one'), $('#two'), $('#three'), $('#four')],//stores the DOM elements to be animated in order
item_index = 0,//stores the current index in the animation queue
animations = {
'0px0px' : { left : '100px', top : '0px' },
'100px0px' : { left : '100px', top : '100px' },
'0px100px' : { left : '0px' , top : '0px' },
'100px100px' : { left : '0px' , top : '100px' }
};//this stores the conversion between where the element is and where it should animate to
//setup a function that can call itself inside the animation callback to iterate through the DOM elements to be animated
function run_animation($element) {
//check to make sure there are more DOM elements to animate, if none are found then the process is done
if (item_index in $items) {
//get this element's top and left CSS properties and put them together so we can convert that to the next coordinates it needs
var css = $items[item_index].css('left') + '' + $items[item_index].css('top');
//now animate this element by converting the current top/left CSS properties to its next coordinates
$items[item_index].animate({
left : animations[css].left,
top : animations[css].top
}, 1500, function () {
//here we run this same function for the next index
item_index++;
run_animation($items[item_index]);
});
}
}
//run the animation function for the first time
run_animation($items[item_index]);
“$(文档).ready(函数(){var i=0;$(“#left”)。单击(函数(){$('.tile')。每个(函数(){i++;var string=“#s”+i.toString();$(string).动画({“left”:“+=50px”},“slow”);})'thanx…我测试了这段代码,但那不起作用,并且做了我写的同样的事情!所有的瓷砖一起移到左边!!!是的…不幸的是,这比刚才要复杂一点。我将制作一个演示,但必须在几秒钟后离开,所以可能需要等待几分钟。对不起,thanx,等待你的时间…我必须解决这个问题。。。我对2个元素使用回调函数,但我不知道如何对可变元素使用它!如何?!为什么在.animate()
函数提供回调时设置超时?@Jasper:因为可以使动画部分重叠,而不是完全按顺序运行。
//first I'm setting up the variables I'll need
var $items = [$('#one'), $('#two'), $('#three'), $('#four')],//stores the DOM elements to be animated in order
item_index = 0,//stores the current index in the animation queue
animations = {
'0px0px' : { left : '100px', top : '0px' },
'100px0px' : { left : '100px', top : '100px' },
'0px100px' : { left : '0px' , top : '0px' },
'100px100px' : { left : '0px' , top : '100px' }
};//this stores the conversion between where the element is and where it should animate to
//setup a function that can call itself inside the animation callback to iterate through the DOM elements to be animated
function run_animation($element) {
//check to make sure there are more DOM elements to animate, if none are found then the process is done
if (item_index in $items) {
//get this element's top and left CSS properties and put them together so we can convert that to the next coordinates it needs
var css = $items[item_index].css('left') + '' + $items[item_index].css('top');
//now animate this element by converting the current top/left CSS properties to its next coordinates
$items[item_index].animate({
left : animations[css].left,
top : animations[css].top
}, 1500, function () {
//here we run this same function for the next index
item_index++;
run_animation($items[item_index]);
});
}
}
//run the animation function for the first time
run_animation($items[item_index]);