Jquery 从API获取数据并在浏览器上显示结果

我使用jQuery从HTML输入字段获取值，将这些值作为变量传递给PHP文件，当连接到API时，PHP文件将接受它们作为URL中的参数

我试图实现的是，当用户输入的纬度和经度值与从API获得的数据不匹配时，它将要求他们输入另一个值，否则它将返回与输入值匹配的地址

API中的数据如下所示：

{"address":{"adminCode2":"0363","adminCode1":"07","lng":"4.88132","distance":"0.02","lat":"52.35792"}}

HTML代码是：

Latitude: <input type="text" id="latitude" name="latitude" placeholder="52.358">
Longitude: <input type="text" id="longitude" name="longitude" placeholder="4.881">

---

您必须通过检查成员是否存在来检查返回的数据是否有效

// Check if the members exist for whichever members you want to access

if(result != null && result.address != null && result.address.lat != null)
{

}

---

我认为您缺少数据的属性。result.data.address，对吗？

<?php
$latitude=$_POST['latitude'];
$longitude=$_POST['longitude'];

$url = "http://api.geonames.org/addressJSON?lat=".$latitude."&lng=".$longitude."&username=username";

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

$response = curl_exec($ch);

if($e = curl_error($ch)) {
     echo $e;
}
else {
$decoded = json_decode($response, true);
// print "<PRE>";
// print_r($decoded);
$encoded = json_encode($decoded);
echo ($encoded);
}
curl_close($ch);

{status: {…}}
status: {message: "missing parameter lat", value: 14}

Uncaught TypeError: Cannot read property 'lat' of undefined

// Check if the members exist for whichever members you want to access

if(result != null && result.address != null && result.address.lat != null)
{

}