如何在jquery中将对象属性从一个数组对象推送到另一个数组对象？

我想要这个-

var result = [
    { Type: "Regular", Code: "abc", Control: "4545", Country: "US", Province: "TX" },
    { Type: "Regular", Code: "abc", Control: "5655455", Country: "US", Province: "TX" },
    { Type: "Regular", Code: "abc", Control: "123", Country: "US", Province: "TX" },
    { Type: "Regular", Code: "abc", Control: "456", Country: "US", Province: "TX" }]

var validation = [
    { valid: "enter correct code" },
    { valid: "control does  not exist" },
    { valid: "control does  not exist" },
    { valid: "control does  not exist" }]

---

有两个对象数组。我想将validation对象的对象属性推送到给定索引处的结果数组对象。如何在jquery中实现这一点？

只需迭代

结果

并设置

结果[索引][“有效”]=验证[索引][“有效”]


var结果=[
{类型：“常规”，代码：“abc”，控制：“4545”，国家：“美国”，省：“德克萨斯州”}，
{类型：“常规”，代码：“abc”，控制：“5655455”，国家：“美国”，省：“德克萨斯州”}，
{类型：“常规”，代码：“abc”，控制：“123”，国家：“美国”，省：“TX”}，
{类型：“常规”，代码：“abc”，控制：“456”，国家：“美国”，省：“德克萨斯州”}]
var验证=[
{valid:“输入正确的代码”}，
{valid:“控件不存在”}，
{valid:“控件不存在”}，
{有效：“控件不存在”}]
for（让index=0；index控制台日志（结果）谢谢，我希望'valid'位于索引1，结果显示'valid'位于最后一个位置。我该怎么做？@harleenkaur然后你必须创建一个新的Json数组，并且你必须按照你想要的正确顺序在该数组中的每个项目中添加key:value对
result= [
    {Type: "Regular", valid: "enter correct code",Code: "abc", Control: "4545", Country: "US", Province:"TX"},
    {Type: "Regular", valid: "control does  not exist", Code: "abc", Control: "5655455", Country: "US", Province:"TX"},
    {Type: "Regular", valid: "control does  not exist", Code: "abc", Control: "123", Country: "US", Province:"TX"},
    {Type: "Regular", valid: "control does  not exist", Code: "abc", Control: "456", Country: "US", Province:"TX"}]