Linux 使用bash脚本创建文件夹和文件

我必须创建50个文件夹，每五个文件夹中应有2*2个文件，例如

folder1
.
.
folder5 - has 2 files in it
folder 6
.
.
folder 10 - has 4 files in it 
.
.
folder 15 - has 8 files in it 

这是我的密码：

#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"

    for (( f = 0; f < n; f++ )) do
    cd Folder$countFolder && touch File$f.txt
    done
done

#/bin/bash
n=1
声明-i countFolder
对于（（countFolder=1；countFolder而言，问题在于您将
cd
放入目录中，但从未
cd
返回

解决此问题的最简单方法是在
cd
周围添加括号。这些括号开始一个子shell，因此
cd
保留在其中：

for (( f = 0; f < n; f++ )) do
  ( cd Folder$countFolder && touch File$f.txt ) 
done

您需要进入目录，创建文件，然后离开。最有效的方法是：

#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
    ls
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"
    cd Folder$countFolder
    for (( f = 0; f < n; f++ )) do
        touch File$f.txt
    done
    cd ..
done

！/bin/bash
n=1
声明-i countFolder
对于（（countFolder=1；countFolder为什么这个问题用python标记？或者触摸文件夹$countFolder/File$f.txt
#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
    ls
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"
    cd Folder$countFolder
    for (( f = 0; f < n; f++ )) do
        touch File$f.txt
    done
    cd ..
done