Loops 需要帮助使用多个命名器对对象的ArrayList进行排序和添加吗

我在排序ArrayList并将结果放入新的ArrayList时遇到了麻烦。 我正在使用Android Studio和Kotlin语言

用户使用salesOrderNr搜索并从服务器接收所有对应的行。 我从服务器接收到ArrayList中的以下数据：

var searchResults: ArrayList<SalesOrder> = [SalesOrder(bulkOrderNr=123, salesOrderNr=112233, salesOrderSet=1, productName="Product 1", productionTime="0:05:00" ),
        SalesOrder(bulkOrderNr=123, salesOrderNr=112233, salesOrderSet=1, productName="Product 2", productionTime="0:12:00" ),
        SalesOrder(bulkOrderNr=123, salesOrderNr=112233, salesOrderSet=1, productName="Product 3", productionTime="0:18:00" ),
        SalesOrder(bulkOrderNr=234, salesOrderNr=112233, salesOrderSet=2, productName="Product 1", productionTime="0:16:00" ),
        SalesOrder(bulkOrderNr=234, salesOrderNr=112233, salesOrderSet=2, productName="Product 2", productionTime="0:11:00" ),
        SalesOrder(bulkOrderNr=, salesOrderNr=112233, salesOrderSet=3, productName="Product 1", productionTime="0:10:00" ),
        SalesOrder(bulkOrderNr=345, salesOrderNr=112233, salesOrderSet=4, productName="Product 1", productionTime="0:02:00" ),
        SalesOrder(bulkOrderNr=345, salesOrderNr=112233, salesOrderSet=4, productName="Product 2", productionTime="0:20:00" ),
        SalesOrder(bulkOrderNr=345, salesOrderNr=112233, salesOrderSet=4, productName="Product 3", productionTime="0:14:00" )]

提前谢谢大家

编辑：我设法弄明白了。我相信还有更简单的方法，但我的解决方案如下：

var bulkOrderList: MutableList<Int> = ArrayList() //Collect all bulk order numbers from result Arraylist

    for (singleLine in searchResults) {
        if (singleLine.bulkOrderNr != null) {
            bulkOrderList.add(singleLine.bulkOrderNr!!)
        } else {
            sortedList.add(singleLine) // If no bulkOrderNr, add item to sortedList
        }
    }

    bulkOrderList = bulkOrderList.distinct() as MutableList<Int> // keep only all unique bulkOrderNr's

    for (bulk in bulkOrderList) {

        val dummyLine: SalesOrder =
            SalesOrder(null, null, null, null, null)

        for (item in searchResults) {

            if (item.bulkOrderNr == bulk) {

                if (dummyLine.bulkOrderNr == null) {
                    dummyLine.bulkOrderNr = item.bulkOrderNr
                }

                if (dummyLine.salesOrderNr == null) {
                    dummyLine.salesOrderNr = item.salesOrderNr
                }

                if (dummyLine.productionOrderSet == null) {
                    dummyLine.productionOrderSet = item.productionOrderSet
                }

                if (dummyLine.productName == null) {
                    dummyLine.productName = item.productName
                } else {
                    dummyLine.productName += "\n${item.productName}"
                }
                
                if (dummyLine.productionTime == null){
                    dummyLine.productionTime = item.productionTime
                } else {
                    //TODO figure out a method to sum time.
                }
            }
        }

        sortedList.add(dummyLine)
    }

    sortedList.sortBy { it -> it.productionOrderSet } //Expected result

var bulkOrderList:MutableList=ArrayList（）//从结果ArrayList收集所有批量订单号
for（搜索结果中的单行）{
if（singleLine.bulkOrderNr！=null）{
bulkOrderList.add（singleLine.bulkOrderNr！！）
}否则{
sortedList.add（单线）//如果没有bulkOrderNr，则将项目添加到sortedList
}
}
bulkOrderList=bulkOrderList.distinct（）作为可变列表//仅保留所有唯一的bulkOrderNr
对于（批量订单列表中的批量）{
val dummyLine：销售订单=
SalesOrder（null，null，null，null，null）
用于（搜索结果中的项目）{
如果（item.bulkOrderNr==批量）{
if（dummyLine.bulkOrderNr==null）{
dummyLine.bulkOrderNr=项目.bulkOrderNr
}
if（dummyLine.salesOrderNr==null）{
dummyLine.salesfordernr=item.salesfordernr
}
if（dummyLine.productionOrderSet==null）{
dummyLine.productionOrderSet=项目.productionOrderSet
}
如果（dummyLine.productName==null）{
dummyLine.productName=item.productName
}否则{
dummyLine.productName+=“\n${item.productName}”
}
if（dummyLine.productionTime==null）{
dummyLine.productionTime=item.productionTime
}否则{
//TODO找出一个求和时间的方法。
}
}
}
sortedList.add（dummyLine）
}
sortedList.sortBy{it->it.productionOrderSet}//预期结果

for (singleLine: SalesOrder in searchResults) {
        
        if (singleLine.bulkOrderNr != null){
            // I am stuck here
        } else {
            correctedList.add(singleLine) // if there is no bulkOrderNr, it means that I can add it to new array directly.
        }

    }

var bulkOrderList: MutableList<Int> = ArrayList() //Collect all bulk order numbers from result Arraylist

    for (singleLine in searchResults) {
        if (singleLine.bulkOrderNr != null) {
            bulkOrderList.add(singleLine.bulkOrderNr!!)
        } else {
            sortedList.add(singleLine) // If no bulkOrderNr, add item to sortedList
        }
    }

    bulkOrderList = bulkOrderList.distinct() as MutableList<Int> // keep only all unique bulkOrderNr's

    for (bulk in bulkOrderList) {

        val dummyLine: SalesOrder =
            SalesOrder(null, null, null, null, null)

        for (item in searchResults) {

            if (item.bulkOrderNr == bulk) {

                if (dummyLine.bulkOrderNr == null) {
                    dummyLine.bulkOrderNr = item.bulkOrderNr
                }

                if (dummyLine.salesOrderNr == null) {
                    dummyLine.salesOrderNr = item.salesOrderNr
                }

                if (dummyLine.productionOrderSet == null) {
                    dummyLine.productionOrderSet = item.productionOrderSet
                }

                if (dummyLine.productName == null) {
                    dummyLine.productName = item.productName
                } else {
                    dummyLine.productName += "\n${item.productName}"
                }
                
                if (dummyLine.productionTime == null){
                    dummyLine.productionTime = item.productionTime
                } else {
                    //TODO figure out a method to sum time.
                }
            }
        }

        sortedList.add(dummyLine)
    }

    sortedList.sortBy { it -> it.productionOrderSet } //Expected result