Matlab 飞机在预期区域之外
创意 我正试图用matlab中的cross绘制一个由两个向量分隔的平面 代码Matlab 飞机在预期区域之外,matlab,matlab-figure,linear-algebra,Matlab,Matlab Figure,Linear Algebra,创意 我正试图用matlab中的cross绘制一个由两个向量分隔的平面 代码 NM= [1 3; 2 4] //matrix figure hold on; z = zeros(size(NM, 1), 1); //to use quiver3 quiver3(z, z, z, NM(:,1), NM(:,2), z, 0); //vectors plotted grid on vi
NM= [1 3; 2 4] //matrix
figure
hold on;
z = zeros(size(NM, 1), 1); //to use quiver3
quiver3(z, z, z, NM(:,1), NM(:,2), z, 0); //vectors plotted
grid on
view(45, 45);
s=sum(NM);
p = 10*(rand(3,1) - 0.5); // generation of points
O1=[NM(1,:) 0] // new vectors of length 3 ,
O2=[NM(2,:) 0] // to be used by cross
v3 = cross(O1,O2) //cross product to find the norm
[ x , y ] = meshgrid( p(1)+(-5:5) , p(2)+(-5:5) ); // points inside the plane
z = p(3) - (v3(1)*(x-p(1)) + v3(2)*(y-p(2)))/v3(3); // plane equation
surf(x,y,z) //the plane itself
输出是
问题平面必须由矢量分隔,或者矢量必须在平面内部而不是外部。矢量不会出现在平面内部,因为当您使平面经过随机选择的点
p
时,选择(0,0,0)
作为矢量的起点
使用quiver3()
打印时,可以使平面经过(0,0,0)
或使用p
作为向量的起点
以下是我选择第二个选项的解决方案:
vplane = [1 3 0; 2 4 0]'; % (column) vectors defining the plane
vnormal = cross(vplane(:,1), vplane(:,2)); % normal defining the orientation of the plane
figure; hold on; grid on; view(45, 45);
rng(1313) % seed for reproducible output
p = 10*(rand(3,1) - 0.5); % a point defining the position of the plane we want to plot with the given normal vector
P = repmat(p, 1, 2); % matrix with the given point repeated for easier use of quiver3()
quiver3(P(1,:), P(2,:), P(3,:), vplane(1,:), vplane(2,:), vplane(3,:), 0); % arrows representing the vectors defining the plane
[x,y] = meshgrid( p(1)+(-5:5), p(2)+(-5:5) ); % set of equally spaced points inside the plane
z = p(3) - (vnormal(1)*(x-p(1)) + vnormal(2)*(y-p(2))) / vnormal(3); % plane equation
surf(x,y,z) % plot the plane
结果如下: