Mongodb Mongoose:在.populate（{match}）中使用$or

我已经建立了这样一个数据库：

const listSchema = new mongoose.Schema({
    name: {
        type: String,
        required: true,
        trim: true
    },
    additionalInfo: {
      type: String,
      required: false
    },
    author: {
        required: true,
        type: mongoose.Schema.Types.ObjectId,
        ref: 'User'
    }
  })

  listSchema.virtual('vocs', {
    ref: 'Voc',
    localField: '_id',
    foreignField: 'list'
  })

  var List = mongoose.model('List', listSchema);

  module.exports = List;

---

现在，我想做的是：我想选择所有具有特定作者的列表，然后接触VOC并通过translationGerman和translationForeignLanguage过滤这些VOC：我想在所有具有特定值的列表中选择所有VOC（让我们说“translationGerman”或“translationForeignLanguage”中的“apple”一词）“translationForeignLanguage”已存储。我尝试了以下代码：

router.get('/api/filterAllWords/:wordname', auth, async (req, res) => {
    try {

        // const words = await Voc.find({$or:[{translationForeignLanguage: req.params.wordname},{translationGerman: req.params.wordname}]});
        // console.log(words);
        // res.send(words)

        const lists = await List.find({author: req.user._id});
        let allVocs = [];

        for (let i = 0; i < lists.length; i++) {
            const singleListVocs = await lists[i].populate(
                {path: "vocs",
                match: {
                    {$or:[{translationForeignLanguage: req.params.wordname},{translationGerman: req.params.wordname}]}
                }}).execPopulate();
            for(let i = 0; i < singleListVocs.vocs.length; i++) {
                allVocs.push(singleListVocs.vocs[i])
            }
        }

        res.send(allVocs)
    }

    catch {
        res.status(404).send({status: 'No vocs found'});
    }
})

router.get（'/api/filteralwords/：wordname'，auth，async（req，res）=>{
试一试{
//const words=wait Voc.find（{$or:[{translationForeignLanguage:req.params.wordname}，{translationGerman:req.params.wordname}]}）；
//控制台日志（文字）；
//res.send（文字）
const lists=wait List.find（{author:req.user.\u id}）；
设allVocs=[]；
for（设i=0；i

当我尝试测试代码时，它会向我发送错误“意外令牌”。我是否使用了$or内部填充（匹配）错误。当我尝试重复此代码时，仅将“translationForeignLanguage:req.params.wordname”作为匹配参数，一切都很好，工作正常

谢谢你的帮助

---

Julia

只要去掉

匹配

（围绕

$或

语句）中多余的花括号，它就可以工作了：

lists[i]
  .populate({
    path: 'vocs',
    match: {
      $or: [
        { translationForeignLanguage: req.params.wordname },
        { translationGerman: req.params.wordname },
      ],
    },
  })
  .execPopulate();

lists[i]
  .populate({
    path: 'vocs',
    match: {
      $or: [
        { translationForeignLanguage: req.params.wordname },
        { translationGerman: req.params.wordname },
      ],
    },
  })
  .execPopulate();