Ms access 如何从基于给定日期的查询中找到一个人的年龄？

我如何通过查询从出生日期算起的给定日期来查找一个人的年龄

我想运行一个查询，返回表中每个人的年龄，从出生日期开始计算下一年的任何日期

我想以年为单位返回他们的年龄，比如说在明年的1/09（9月）

今天的日期是2015年9月2日

如果出生日期是2006年10月9日，答案是9

如果出生日期是2006年1月28日，答案是10

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有什么想法吗？？有人吗？

UNIX\u时间戳（NOW（））-UNIX\u时间戳（表中的日期）以秒为单位显示差异。现在只需转换为年。

您可以在表单上文本框的控制源中使用表达式 当前日期：2015年1月1日

Table1:
|Birth_Date |
|01/01/1995 | = 20
|01/01/1994 | = 21

表达方式： =DateDiff（“yyyy”，[出生日期]，日期（））

每次打开表单时，年龄都会更新

或

VBA（需要一个按钮）

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DateDiff仅返回日历年中的差异

对于今天的真实年龄，请使用以下函数：

Public Function AgeSimple( _
  ByVal datDateOfBirth As Date) _
  As Integer

' Returns the difference in full years from datDateOfBirth to current date.
'
' Calculates correctly for:
'   leap years
'   dates of 29. February
'   date/time values with embedded time values
'
' DateAdd() is used for check for month end of February as it correctly
' returns Feb. 28. when adding a count of years to dates of Feb. 29.
' when the resulting year is a common year.
' After an idea of Markus G. Fischer.
'
' 2007-06-26. Cactus Data ApS, CPH.

  Dim datToday  As Date
  Dim intAge    As Integer
  Dim intYears  As Integer

  datToday = Date
  ' Find difference in calendar years.
  intYears = DateDiff("yyyy", datDateOfBirth, datToday)
  If intYears > 0 Then
    ' Decrease by 1 if current date is earlier than birthday of current year
    ' using DateDiff to ignore a time portion of datDateOfBirth.
    intAge = intYears - Abs(DateDiff("d", datToday, DateAdd("yyyy", intYears, datDateOfBirth)) > 0)
  End If

  AgeSimple = intAge

End Function

对于任何日期组合，请使用此函数：

Public Function Years( _
  ByVal datDate1 As Date, _
  ByVal datDate2 As Date, _
  Optional ByVal booLinear As Boolean) _
  As Integer

' Returns the difference in full years between datDate1 and datDate2.
'
' Calculates correctly for:
'   negative differences
'   leap years
'   dates of 29. February
'   date/time values with embedded time values
'   negative date/time values (prior to 1899-12-29)
'
' Optionally returns negative counts rounded down to provide a
' linear sequence of year counts.
' For a given datDate1, if datDate2 is decreased step wise one year from
' returning a positive count to returning a negative count, one or two
' occurrences of count zero will be returned.
' If booLinear is False, the sequence will be:
'   3, 2, 1, 0,  0, -1, -2
' If booLinear is True, the sequence will be:
'   3, 2, 1, 0, -1, -2, -3
'
' If booLinear is False, reversing datDate1 and datDate2 will return
' results of same absolute Value, only the sign will change.
' This behaviour mimics that of Fix().
' If booLinear is True, reversing datDate1 and datDate2 will return
' results where the negative count is offset by -1.
' This behaviour mimics that of Int().

' DateAdd() is used for check for month end of February as it correctly
' returns Feb. 28. when adding a count of years to dates of Feb. 29.
' when the resulting year is a common year.
'
' 2000-11-03. Cactus Data ApS, CPH.
' 2000-12-16. Leap year correction modified to be symmetrical.
'             Calculation of intDaysDiff simplified.
'             Renamed from YearsDiff() to Years().
' 2000-12-18. Introduced cbytMonthDaysMax.
' 2007-06-22. Version 2. Complete rewrite.
'             Check for month end of February performed with DateAdd()
'             after idea of Markus G. Fischer.

  Dim intDiff   As Integer
  Dim intSign   As Integer
  Dim intYears  As Integer

  ' Find difference in calendar years.
  intYears = DateDiff("yyyy", datDate1, datDate2)
  ' For positive resp. negative intervals, check if the second date
  ' falls before, on, or after the crossing date for a full 12 months period
  ' while at the same time correcting for February 29. of leap years.
  If DateDiff("d", datDate1, datDate2) > 0 Then
    intSign = Sgn(DateDiff("d", DateAdd("yyyy", intYears, datDate1), datDate2))
    intDiff = Abs(intSign < 0)
  Else
    intSign = Sgn(DateDiff("d", DateAdd("yyyy", -intYears, datDate2), datDate1))
    If intSign <> 0 Then
      ' Offset negative count of years to continuous sequence if requested.
      intDiff = Abs(booLinear)
    End If
    intDiff = intDiff - Abs(intSign < 0)
  End If

  ' Return count of years as count of full 12 months periods.
  Years = intYears - intDiff

End Function

公共职能年（_
ByVal DatDate 1作为日期_
ByVal DatDate 2作为日期_
可选的ByVal booLinear（作为布尔值）_
作为整数
'返回datDate1和datDate2之间的全年差值。
'
'正确计算：
"负差异",
“闰年
"29日。二月
'带有嵌入时间值的日期/时间值
'负日期/时间值（1899-12-29之前）
'
'可选地返回向下舍入的负计数，以提供
“年度计数的线性序列。
'对于给定的datDate1，如果datDate2从
'返回正计数到返回负计数，一个或两个
'将返回计数为零的事件。
'如果booLinear为False，则序列为：
'   3, 2, 1, 0,  0, -1, -2
'如果booLinear为真，则序列将为：
'   3, 2, 1, 0, -1, -2, -3
'
'如果booLinear为False，则将返回反向的datDate1和datDate2
'相同绝对值的结果，只有符号会改变。
'此行为模仿Fix（）。
'如果booLinear为True，则将返回反向的datDate1和datDate2
'负计数被-1偏移的结果。
'此行为模仿Int（）的行为。
'DateAdd（）用于检查2月底，因为它正确
2月28日返回。在2月29日的日期上加上年数。
“当产生的年份是普通年份时。
'
' 2000-11-03. 仙人掌数据ApS，CPH。
' 2000-12-16. 闰年修正修改为对称。
'简化了intDaysDiff的计算。
'已从YearsDiff（）重命名为Years（）。
' 2000-12-18. 介绍了cbytMonthDaysMax。
' 2007-06-22. 版本2。完全重写。
'使用DateAdd（）执行的2月底检查'
“在马库斯·G·费舍尔的想法之后。
Dim intDiff作为整数
整数形式的整数符号
整数形式的整数
'查找日历年的差异。
intYears=DateDiff（“yyyy”，datDate1，datDate2）
“积极响应。负间隔，检查第二个日期
在穿越日期之前、当天或之后的整整12个月内
同时对2月29日进行修正。闰年。
如果DateDiff（“d”，datDate1，datDate2）>0，则
intSign=Sgn（DateDiff（“d”，DateAdd（“yyyy”，INTYERS，DATDATATE1），DATATE2））
intDiff=Abs（intSign<0）
其他的
intSign=Sgn（日期差异（“d”，日期添加（“yyyy”，-intYears，datDate2），datDate1））
如果输入0，那么
'如有要求，将年的负计数抵消为连续序列。
intDiff=Abs（booLinear）
如果结束
intDiff=intDiff-Abs（intSign<0）
如果结束
'返回年数作为完整12个月期间的计数。
年份=整数年-整数年
端函数

查看

DateDiff

应该做你想做的事

Public Function Years( _
  ByVal datDate1 As Date, _
  ByVal datDate2 As Date, _
  Optional ByVal booLinear As Boolean) _
  As Integer

' Returns the difference in full years between datDate1 and datDate2.
'
' Calculates correctly for:
'   negative differences
'   leap years
'   dates of 29. February
'   date/time values with embedded time values
'   negative date/time values (prior to 1899-12-29)
'
' Optionally returns negative counts rounded down to provide a
' linear sequence of year counts.
' For a given datDate1, if datDate2 is decreased step wise one year from
' returning a positive count to returning a negative count, one or two
' occurrences of count zero will be returned.
' If booLinear is False, the sequence will be:
'   3, 2, 1, 0,  0, -1, -2
' If booLinear is True, the sequence will be:
'   3, 2, 1, 0, -1, -2, -3
'
' If booLinear is False, reversing datDate1 and datDate2 will return
' results of same absolute Value, only the sign will change.
' This behaviour mimics that of Fix().
' If booLinear is True, reversing datDate1 and datDate2 will return
' results where the negative count is offset by -1.
' This behaviour mimics that of Int().

' DateAdd() is used for check for month end of February as it correctly
' returns Feb. 28. when adding a count of years to dates of Feb. 29.
' when the resulting year is a common year.
'
' 2000-11-03. Cactus Data ApS, CPH.
' 2000-12-16. Leap year correction modified to be symmetrical.
'             Calculation of intDaysDiff simplified.
'             Renamed from YearsDiff() to Years().
' 2000-12-18. Introduced cbytMonthDaysMax.
' 2007-06-22. Version 2. Complete rewrite.
'             Check for month end of February performed with DateAdd()
'             after idea of Markus G. Fischer.

  Dim intDiff   As Integer
  Dim intSign   As Integer
  Dim intYears  As Integer

  ' Find difference in calendar years.
  intYears = DateDiff("yyyy", datDate1, datDate2)
  ' For positive resp. negative intervals, check if the second date
  ' falls before, on, or after the crossing date for a full 12 months period
  ' while at the same time correcting for February 29. of leap years.
  If DateDiff("d", datDate1, datDate2) > 0 Then
    intSign = Sgn(DateDiff("d", DateAdd("yyyy", intYears, datDate1), datDate2))
    intDiff = Abs(intSign < 0)
  Else
    intSign = Sgn(DateDiff("d", DateAdd("yyyy", -intYears, datDate2), datDate1))
    If intSign <> 0 Then
      ' Offset negative count of years to continuous sequence if requested.
      intDiff = Abs(booLinear)
    End If
    intDiff = intDiff - Abs(intSign < 0)
  End If

  ' Return count of years as count of full 12 months periods.
  Years = intYears - intDiff

End Function