Mysql 带左联接子查询的sql

所以我想问一下，是否可以将这两个查询合并起来。我有三张桌子： 养蜂场可以有多个蜂巢 蜂巢一次只能在一个养蜂场 movedate蜂房和蜂房之间的m:n表，蜂房位于蜂房上时带有日期字段

我的第一个是，它只是得到了用户的蜂巢：

SELECT apiary_id as id, name
            FROM
            apiary 
            WHERE
            modus = '1' //if apiary is aktive
            AND
            user_id = ?

第二个则计算当前每个蜂房上有多少个蜂箱：

SELECT 
            COUNT(*) AS count
            FROM 
            movedate 
                LEFT JOIN //get rows with the same apiary_id
                apiary
                ON
                movedate.apiary_id = apiary.apiary_id
                LEFT JOIN //get rows with the same hive_id
                hive
                ON
                movedate.hive_id = hive.hive_id
                LEFT OUTER JOIN  //outer join to check for the joungest date
                movedate as movedate2
                ON movedate.hive_id = movedate2.hive_id
                    AND (movedate.date < movedate2.date
                    OR (movedate.date = movedate2.date AND movedate.id < movedate2.id))
            WHERE 
            hive.modus = '1'  //check if hive is active
            AND
            apiary.apiary_id = $ap_id  //get apiary id (at the moment to this query for each apiary)
            AND
            movedate2.hive_id IS NULL  (dont get the old entries)

我试图简单地将整个第二个SQL查询作为SELECT中的子查询移动到第一个SQL查询中，但似乎无法在SELECT子查询中执行左连接？如果要使用特殊命令，我将使用PDO

我很乐意得到任何提示

干杯 汉内斯

我想你只需要一组人：

---

太棒了，我的想法太复杂了非常感谢你！

SELECT apiary.apiary_id, COUNT(*) AS count
FROM movedate LEFT JOIN //get rows with the same apiary_id
     apiary
     ON movedate.apiary_id = apiary.apiary_id LEFT JOIN //get rows with the same hive_id
     hive
     ON movedate.hive_id = hive.hive_id LEFT OUTER JOIN  //outer join to check for the joungest date
     movedate as movedate2
     ON movedate.hive_id = movedate2.hive_id AND
        (movedate.date < movedate2.date OR
         (movedate.date = movedate2.date AND movedate.id < movedate2.id)
        )
WHERE hive.modus = '1' AND //check if hive is active
      movedate2.hive_id IS NULL  (dont get the old entries)
GROUP BY apiary.apiary_id;