Mysql 查询以检索用户信息谁'；的购物车大于所有用户的平均值

我需要编写一个查询来获得一个客户列表，其中所有订单的总和大于所有客户的平均值。我不允许使用子查询

select id_client, surname, id_order, data, count(*) as position_t, sum(shop_quantity) as quantity, 
sum(shop_quantity*d.price) as summa_order, (select avg(shop_quantity*d.price) from shopping_cart join product d on id_product = fk_product) as average
from client a
join `order` b on id_client = fk_client
join shopping_cart c on id_order = fk_order
join product d on id_product = fk_product 
join catalog e on id_catalog = fk_catalog
group by id_order
having summa_order > average
order by summa_order desc;

它应该是这样的，但是没有子查询。怎么写？ 输出在这里：

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注意：其他聚合函数也应起作用（求和、计数）

您可以使用聚合函数：

select 
    id_client
    , surname
    , id_order
    , data
    , count(*) as position_t
    , sum(shop_quantity) as quantity
    , SUM(shop_quantity*d.price) as summa_order
    , AVG(shop_quantity*d.price) OVER ( PARTITION BY shopping_cart.id_product) AS      average
from client a
join `order` b 
    on id_client = fk_client
join shopping_cart c 
    on id_order = fk_order
join product d 
    on id_product = fk_product 
join catalog e 
    on id_catalog = fk_catalog
group by id_order
having summa_order > average
order by summa_order desc;

我没有更改GROUPBY，但您需要GROUPBY语句中select的所有非聚合列