如何在MySQL中选择具有左联接表的上一条记录?

如何在MySQL中选择具有左联接表的上一条记录?,mysql,select,left-join,records,Mysql,Select,Left Join,Records,我正在努力使以下各项发挥作用: # prev SELECT klha.buyerID < PARAMETER_1 FROM agents AS v LEFT JOIN seller_authorized AS klhs ON klhs.agent= v.agentID AND klhs.iln = v.seller AND v.`status` = 'auth' LEFT JOIN cust_list AS

我正在努力使以下各项发挥作用:

# prev
SELECT klha.buyerID < PARAMETER_1

    FROM agents AS v

    LEFT JOIN seller_authorized AS klhs 
        ON klhs.agent= v.agentID 
        AND klhs.iln = v.seller
        AND v.`status` = 'auth'

    LEFT JOIN cust_list AS klha 
        ON klha.buyerID  = klhs.userID
        AND klha.accountNo = klhs.accountNo
        WHERE v.iln = PARAMETER_2
        AND klhs.acccountNo IS NOT NULL

    ORDER BY klha.buyerID 
    LIMIT 1 
;
结束

左连接正在工作,因为我正在另一个过程中使用它们来选择所有相关记录。问题在于我试图选择上一条记录

我正在传递一个buyerID,需要返回上一条记录的id

问题: 有人能告诉我正确的语法吗

编辑: 如果我在MySQL中运行这个,我将得到0作为结果集

谢谢

解决方案: 让它像这样工作:

# prev
SELECT klha.buyerID

    FROM agents AS v

    LEFT JOIN seller_authorized AS klhs 
        ON klhs.agent= v.agentID 
        AND klhs.iln = v.seller
        AND v.`status` = 'auth'

    LEFT JOIN cust_list AS klha 
        ON klha.buyerID  = klhs.userID
        AND klha.accountNo = klhs.accountNo
        WHERE v.iln = PARAMETER_2
        AND klhs.acccountNo IS NOT NULL
        AND klha.buyerID < PARAMETER_1

    ORDER BY klha.buyerID 
    LIMIT 1 
;

比想象的容易:-谢谢@Henrique Ordine

如果我正确理解了您的需要,将此条件添加到where子句中应该可以实现以下目的:

和klha.buyerID=从代理中选择maxbuyerID,其中buyerID<参数_1

像这样:

SELECT klha.buyerID 

    FROM agents AS v

    LEFT JOIN seller_authorized AS klhs 
        ON klhs.agent= v.agentID 
        AND klhs.iln = v.seller
        AND v.`status` = 'auth'

    LEFT JOIN cust_list AS klha 
        ON klha.buyerID  = klhs.userID
        AND klha.accountNo = klhs.accountNo
    WHERE v.iln = PARAMETER_2
      AND klhs.acccountNo IS NOT NULL
      and klha.buyerID = (select max(buyerID) from agents 
                            where buyerID < PARAMETER_1)

    ORDER BY klha.buyerID 
    LIMIT 1 

啊好的。我不能只是在我的初始选择,可以吗?对不起,我不理解你的问题。做了一些调整。见上文。谢谢欢迎我很高兴能帮上忙。