Mysql 简化此查询

你知道简化这个查询的方法吗？

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认为

您需要这样的用例语句：

SELECT COUNT( sendbook.id ) AS total, SUM( sendbook.num ) AS num, (

SELECT COUNT( sendbook.id )
FROM sendbook
INNER JOIN clients ON clients.id = sendbook.clientid
WHERE sendbook.issueid = '29'
AND clients.area >1000
AND clients.area <2000
) AS area1000, (

SELECT COUNT( sendbook.id )
FROM sendbook
INNER JOIN clients ON clients.id = sendbook.clientid
WHERE sendbook.issueid = '29'
AND clients.area >2000
AND clients.area <3000
) AS area2000, (

SELECT COUNT( sendbook.id )
FROM sendbook
INNER JOIN clients ON clients.id = sendbook.clientid
WHERE sendbook.issueid = '29'
AND clients.area >3000
AND clients.area <4001
) AS area2000
FROM `sendbook`
WHERE sendbook.issueid = '29' 

total  num  area1000  area2000  area2000
 8      438      3         3        2

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您的第二个“area2000”不应该命名为“area3000”吗？区域2000和3000会发生什么情况？您的查询中不考虑这些区域，对吗？您的案例是4行，但我的案例是1行是的，但这是一个非常简单的查询，您只需要运行一个小循环

SELECT  COUNT( sendbook.id ),
(CASE 
WHEN clients.area between '1000' and '2000'  THEN 1 
WHEN clients.area between '2000' and '3000'  THEN 2 
WHEN clients.area between '3000' and '4000'  THEN 3 
 END) AS myrange  FROM mytable 
GROUP BY myrange