MySQL Union语句和计数

我试图计算同一标题出现的次数

我的代码

SELECT 

client AS Client,
datescanned as "Date Scanned",
scanner AS Scanner,
risk AS Risk, 
host AS Host, 
name AS Title, 
solution AS Solution
FROM sss1webapp_latest

WHERE risk regexp "Critical|High" 
AND client = "myself" 
group by Title;

UNION

SELECT 


client AS Client,
datescanned as "Date Scanned",
scanner AS Scanner,
AttackScore AS Risk, 
WebSite AS Host, 
AttackType AS Title, 
Recommendation AS Solution
FROM sss2webapp_latest
WHERE AttackScore regexp "5-Critical|4-High" 
AND client = "myself"

我的表只是一个表示，没有添加所有字段

client  datescanned  title  ....
myself  2019-03-11  Backported Security Patch 
myself  2019-03-11  Backported Security Patch
myself  2019-03-11  Backported Security Patch Detection (SSH)
myself  2019-03-11  Backported Security Patch Detection (SSH)
myself  2019-03-11  Backported Security Patch Detection (SSH)
myself  2019-03-11  Backported Security Patch Detection (SSH)
myself  2019-03-11  SSL Version Issues

我的期望输出

count client datescanned title
2     myself  2019-03-11    Backported Security Patch 
4     myself  2019-03-11    Backported Security Patch Detection (SSH)
1     myself  2019-03-11    SSL Version Issues

添加计数和分组相同的标题，并计数出现的次数

尝试在select语句后添加count0as tcount，但出现错误

欢迎反馈！ 谢谢！纳塔莉

 select count(*) as count, client, datescanned, title, risk AS Risk  
 from sss1webapp_latest 
 where risk regexp "Critical|High" AND client = "myself"  group by title 

 union

 select count(*) as count, client, datescanned, title, AttackScore AS Risk 
 from sss2webapp_latest 
 where AttackScore regexp "5-Critical|4-High" AND client = "myself" group by title 

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您可以选择其他列，但列号应相同，并且union的名称也应相同

我认为我能够使用count*和sum*的组合实现所需的结果。您可能应该使用ALL作为联合，而不是联合，因为我们希望统计重复记录。查看此db小提琴：

您可能需要通过添加额外的列和where子句来稍微调整查询

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我从另一个答案中总结出这个想法：

您的第一个select语句上有一个额外的分号按标题分组；我试过了。。如果我在一个没有并集的语句中添加count作为count，就可以了。然而，只要我加上几个计数，我就得到了无法计算0在并集中的位置选择count0作为计数；客户作为客户，扫描日期作为扫描日期。。。。。。。。