Mysql 同一项目中的员工和经理？SQL

我做了一些挖掘，但无法在脑海中安排它。。。我的问题是找到同一项目中的员工和经理？我有两个表，分别是Employee和Project。他们喜欢

   *Employee*               
   ----------               
   employee_id (PK)          
   name
   manager_id (FK)   ref employee_id in same table which is employee_id.
   usertype    

   *Project*
   ----------
   project_id(PK)
   project_name
   employee_id(FK)   ref employee_id in emplyee table
   manager_id(FK)    ref employee_id in emplyee table

让我更具体一点。项目必须有一名经理和多名员工。如何在查询中写入？usertype列指定此员工经理或USERnormal员工

查询运行示例：

       ______    ______________    ____________
       |name|    |manager_name|   |project_name|  
        John         Susan       CalendarIphone
        Mike         Susan       CalendarIphone
        Joe         Patrick        AndoridApp
        Megan        Susan        CalendarIphone
        Melek       Patrick        AndoridApp

正如您所见，Mike可以在多个项目中工作，并且可以有多个经理。但管理者必须只拥有一个项目。那么我应该怎么做才能得到这个呢？先谢谢你

编辑----------------------------------------

我有一个项目，其中有下拉列表。我在这里选择了一个项目，它给我显示了一个根据这个项目的表格，并列出了我这个项目的经理，那个项目的员工。我问项目名称，只要再创建一列就可以忽略它。我只想看到it经理和it员工

编辑2------------------------------

例如，项目ID=2，在这个项目中，我们有1名经理和员工

   |name|    |manager_name|    
    John         Susan      
    Mike         Susan       
    Joe          Susan       
    Megan        Susan       
    Melek        Susan

---

由于每个项目行都有员工和经理，因此只需在两个不同的键上转到employee表即可获得员工和经理的姓名。然后，很自然地以项目为基础进行查询，因为这是您正在收集的信息，所以您可以从中提取项目名称。

您的模式不好。应该是这样的：

   Employee*               
   ----------               
   employee_id (PK)          
   name
   manager_id (FK)   ref employee_id in employee table

   *Project*
   ----------
   project_id(PK)
   project_name
   manager_id(FK)    ref employee_id in employee table

   *Project_Employee*
   ----------
   project_id(FK)  ref project_id in project table
   employee_id(FK) ref employee_id in employee table

然后你可以做：

   select
       e.name as name,
       em.name as manager_name
       p.project_name
       pm.name as project_manager_name
   from Employee as e
       left outer join Employee as em on em.employee_id = e.manager_id
       left outer join Project_Employee as pe on pe.employee_id = e.employee_id
       left outer join Project as p on p.project_id = pe.project_id
       left outer join Employee as pm on pm.employee_id = p.manager_id

但对于每个员工，可能有多个项目，员工可以在这个查询中重复

更新

更新2

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如果Mike的经理因项目而异，那么它在employee表和project表中都没有位置。它应该在项目员工表中，我不知道经理也是员工？经理id应该指员工id吗？谢谢你的回答。。。你建议避免重复什么？在你的问题中有重复的标记。你可以使用group_concat让employe的所有项目都以逗号分隔，例如，我不知道你的目标是什么。我明白你的意思。请看一下我的编辑。提前感谢检查更新的查询。我仍然没有得到您的确切要求，我的查询将返回您的员工列表，bit属性是_manager谢谢您的回答，它会有所帮助。让我再问你们一次：我想在同一个项目中得到经理和员工的名字。但经理不能有超过1个项目。员工可以在多个项目上工作。当我运行查询时，它应该在我的上次更新中返回：请参阅答案

   select
       e.name as name,
       em.name as manager_name
       p.project_name
       pm.name as project_manager_name
   from Employee as e
       left outer join Employee as em on em.employee_id = e.manager_id
       left outer join Project_Employee as pe on pe.employee_id = e.employee_id
       left outer join Project as p on p.project_id = pe.project_id
       left outer join Employee as pm on pm.employee_id = p.manager_id

 select
     e.name, u.is_manager
 from (
     select employee_id, 0 as is_manager from Project_Employee as pe where pe.idproject_id= <project id>
     union all
     select manager_id, 1 as is_manager from Project as p where p.project_id= <project id>
 ) as u
     inner join Employee as e on e.employee_id = u.employee_id
 order by u.is_manager desc

select
    e.name as employee_name,
    pm.name as manager_name
from Project_Employee as pe
    left outer join Employee as e on e.employee_id = pe.employee_id
    left outer join Project as p on p.project_id = pe.project_id
    left outer join Employee as pm on pm.employee_id = p.manager_id
where pe.project_id = <project id>