当有分组依据时，MySQL自定义订单依据

我想知道当我以前使用group BY时如何使用自定义ORDER BY

这是我的问题

SELECT
CASE WHEN a.edad < 40 THEN 'Menos de 40'
     WHEN a.edad >= 40 AND a.edad <=49 THEN 'De 40 a 49'
     WHEN a.edad >= 50 AND a.edad <=59 THEN 'De 50 a 59'
     WHEN a.edad >= 60 AND a.edad <=69 THEN 'De 60 a 69'
     WHEN a.edad >=70 THEN 'De 70 y más'
      ELSE(SELECT a.edad) END AS 'Grupo de edad',
      SUM(IF(a.sexo='F',1,0)) AS Mujeres,SUM(IF(a.sexo='M',1,0)) AS Hombres
FROM academicos a
WHERE CCN REGEXP 'I|D65' /*Tomando en cuenta a la persona docente*/
GROUP BY 1

我希望文本

'Menos de 40'，2，0

出现在顶部。

---

如何实现这一点？

您必须使用稍微不同的返回标准将

CASE

语句复制到

ORDER BY

子句中。我尽我所能把你的问题翻译成英语，我没有不尊重的意思

查询：

SELECT 
  CASE WHEN age < 40 THEN 'Less than 40'
       WHEN age >= 40 AND age <= 49 THEN 'From 40 to 49'
       WHEN age >= 50 AND age <= 59 THEN 'From 50 to 59'
       WHEN age >= 60 AND age <= 69 THEN 'From 60 to 69'
       ELSE age END AS 'Age Grouping',
  SUM(IF(sex = 'F', 1, 0)) AS 'Girls',
  SUM(IF(sex = 'M', 1, 0)) AS 'Boys'
FROM students
GROUP BY 1
ORDER BY 
  CASE WHEN age < 40 THEN 1
       WHEN age >= 40 AND age <= 49 THEN 2
       WHEN age >= 50 AND age <= 59 THEN 3
       WHEN age >= 60 AND age <= 69 THEN 4
       ELSE 5 END

+---------------+-------+------+ | Age Grouping | Girls | Boys | +---------------+-------+------+ | Less than 40 | 1 | 2 | | From 40 to 49 | 0 | 1 | | From 50 to 59 | 0 | 1 | | From 60 to 69 | 0 | 1 | +---------------+-------+------+

选择
如果年龄<40岁，则“小于40”
当年龄>=40岁，年龄=50岁，年龄=60岁，年龄=40岁，年龄=50岁，年龄=60岁，你在心理上应用的标准是什么，应该使记录处于顶部？这就成功了！顺便说一句，谢谢你把这个问题翻译成英语。
+---------------+-------+------+
| Age Grouping  | Girls | Boys |
+---------------+-------+------+
| Less than 40  |     1 |    2 |
| From 40 to 49 |     0 |    1 |
| From 50 to 59 |     0 |    1 |
| From 60 to 69 |     0 |    1 |
+---------------+-------+------+