Mysql 来自另一个表的SUM（）的条件？

我有这样的数据表

id | amount | payment | balance
1  | 200    | 200     | 0
2  | 300    | 250     | 50

表

交易

ID | Amount
1  | 200
2  | 300

表

付款

ID | Transaction | Amount
1  | 1           | 200
2  | 2           | 150
3  | 2           | 100

然后我使用查询

SELECT `transaction`.id AS `id`,
    `transaction`.amount AS amount,
    SUM(payment.amount) AS payment,
    `transaction`.amount - SUM(payment.amount) AS balance
FROM `transaction`
LEFT JOIN payment
    ON payment.`transaction` = `transaction`.id
GROUP BY payment.`transaction`;

然后我得到这样的数据

id | amount | payment | balance
1  | 200    | 200     | 0
2  | 300    | 250     | 50

现在，我如何使条件仅显示余额大于0的数据？
它应该只显示行id 2

我试图做这个查询，但它给了我错误

SELECT `transaction`.id AS `id`,
    `transaction`.amount AS amount,
    SUM(payment.amount) AS payment,
    `transaction`.amount - SUM(payment.amount) AS balance
FROM `transaction`
LEFT JOIN payment
    ON payment.`transaction` = `transaction`.id
WHERE `transaction`.amount - SUM(payment.amount) > 0
GROUP BY payment.`transaction`;

谢谢你，
Gusde

HAVING”SQL子句满足您的需要。它类似于“WHERE”，只是它在join和groupby之后运行，并允许您根据几乎最终的输出进行过滤。它还可用于查找已连接在一起的表之间缺少的关系

SELECT `transaction`.id AS `id`,
   `transaction`.amount AS amount,
    SUM(payment.amount) AS payment,
    `transaction`.amount - SUM(payment.amount) AS balance
FROM `transaction`
LEFT JOIN payment
    ON payment.`transaction` = `transaction`.id
GROUP BY payment.`transaction`
HAVING balance > 0;