Oracle 如何在列表中使用chr（10）？

我需要在listagg中插入一个char（10），但它没有按预期工作

select ID, listagg(value , chr(10))within group (order by ID) as "value"
from DTA 
group by ID

以下是我写的脚本：

select ID, listagg(value , ';')within group (order by ID) as "value"
from DTA 
group by ID


Current Result
ID  |value      |
----|-----------|
1   |aaa;bbb;ccc|
2   |abc        |
3   |abe        |


Desired Result 

ID  |value          
----|------
1   |aaa            
    |bbb                
    |ccc            
----|------
2   |abc            
----|------
3   |abe

我试着用这个，但没有达到预期效果

select ID, listagg(value , chr(10))within group (order by ID) as "value"
from DTA 
group by ID

---

如何改进脚本？

您的代码是正确的。您需要一个能够显示换行符的工具：

WITH DTA AS (
  SELECT 1 AS ID, 'A' AS Value FROM dual
  UNION ALL
  SELECT 1 AS ID, 'B' FROM dual
)
select ID, listagg(value , chr(10))within group (order by ID) as "value"
from DTA 
group by ID;

输出：

ID  value
1   A
    B

---

使用PIVOT尝试下面的查询，使用listag很难实现chr（10）

WITH sample_data AS (SELECT 1 ID,  'aaa' value FROM dual UNION ALL
                     SELECT 1 ID,  'bbb' value FROM dual UNION ALL
                     SELECT 1 ID,  'ccc' value FROM dual UNION ALL
                     SELECT 2 ID,  'abc' value FROM dual UNION ALL
                     SELECT 3 ID,  'abe' value FROM dual )

SELECT CASE WHEN row_number() OVER (PARTITION BY DTA_ID
                                    ORDER BY CASE 
                                                  WHEN column_name = 'VALUE' THEN 1
                                             END) = 1
                 THEN DTA_ID
       END "Current ID",
       vals "Result Value"
FROM (SELECT ID DTA_ID,
               VALUE 
        FROM   sample_data)
UNPIVOT (vals FOR column_name IN ("VALUE"))
ORDER BY DTA_ID;

---

这可能有助于满足您的要求

select ID, listagg(value , || CHR (10)) within group (order by ID) as "value"