Oracle HAVING子句中的2x计数

我有以下问题： 我想在一个表中统计数据，在第二个表中统计数据，并在having子句中比较计数，并且只显示具有相同计数的行 诸如此类：

SELECT bla
FROM T1 t1 JOIN T2 t2
ON t1.id = t2.id
HAVING COUNT(counted data from table1) = COUNT(counted data from table2)

你知道吗？ 干杯

标准SQL：

SELECT t1.bla, t1.id, t1.counter, t2.counter
  FROM (SELECT t1.bla, t1.id, COUNT(counted_data_from_t1) AS counter
          FROM t1
         GROUP BY t1.bla, t1.id
       ) AS t1
  JOIN (SELECT t2.id, COUNT(counted_data_from_t2) AS counter
          FROM t2
         GROUP BY t2.id
       ) AS t2
    ON t1.id = t2.id AND t1.counter = t2.counter

Oracle SQL，因为Oracle不喜欢以前的表别名：

SELECT t1.bla, t1.id, t1.counter, t2.counter
  FROM (SELECT t1.bla, t1.id, COUNT(counted_data_from_t1) AS counter
          FROM t1
         GROUP BY t1.bla, t1.id
       ) t1
  JOIN (SELECT t2.id, COUNT(counted_data_from_t2) AS counter
          FROM t2
         GROUP BY t2.id
       ) t2
    ON t1.id = t2.id AND t1.counter = t2.counter

你只需要决定bla来自哪里；我提名了t1。我假设对于任何给定的t1.id值，都有一个值t1.bla。如果没有，那么您需要更清楚地解释您正在计算的内容、各个列的位置以及表的键是什么

更新：很抱歉没有注意到Oracle标记并给出无效的Oracle语法。

标准SQL:

SELECT t1.bla, t1.id, t1.counter, t2.counter
  FROM (SELECT t1.bla, t1.id, COUNT(counted_data_from_t1) AS counter
          FROM t1
         GROUP BY t1.bla, t1.id
       ) AS t1
  JOIN (SELECT t2.id, COUNT(counted_data_from_t2) AS counter
          FROM t2
         GROUP BY t2.id
       ) AS t2
    ON t1.id = t2.id AND t1.counter = t2.counter

WITH jezyki as 
          (SELECT pseudo_wampira, COUNT(*) AS counter
            FROM Jezyki_obce_w
            GROUP BY pseudo_wampira
          )
    ,sprawnosc as 
         (SELECT pseudo_wampira, sprawnosc, COUNT(*) AS counter
          FROM Sprawnosci_w
         GROUP BY pseudo_wampira, sprawnosc 
         )
      SELECT jezyki.pseudo_wampira, sprawnosc.counter
        FROM jezyki,sprawnosc
       WHERE  jezyki.pseudo_wampira = sprawnosc.pseudo_wampira 
         AND  jezyki.counter = sprawnosc.counter

Oracle SQL，因为Oracle不喜欢以前的表别名：

SELECT t1.bla, t1.id, t1.counter, t2.counter
  FROM (SELECT t1.bla, t1.id, COUNT(counted_data_from_t1) AS counter
          FROM t1
         GROUP BY t1.bla, t1.id
       ) t1
  JOIN (SELECT t2.id, COUNT(counted_data_from_t2) AS counter
          FROM t2
         GROUP BY t2.id
       ) t2
    ON t1.id = t2.id AND t1.counter = t2.counter

你只需要决定bla来自哪里；我提名了t1。我假设对于任何给定的t1.id值，都有一个值t1.bla。如果没有，那么您需要更清楚地解释您正在计算的内容、各个列的位置以及表的键是什么

---

更新：很抱歉没有注意到Oracle标记并给出无效的Oracle语法。

计算什么？？选择count*fromt1将返回总行数，您不能将其应用于检查其他表中的行，您能详细说明一下吗？什么是计数？？select count*from T1将返回总行数，您不能将其应用于检查其他表中的行，您能详细说明一下吗？我是按照您的方式执行的，但有一个错误行5，第9列，SQL命令未正确结束select PSUDE_wampira中的select jezyki.PSUDE_wampira，sprawnosc.counter，通过伪wampira从Jezyki_-obce_-w组中计数*作为计数器作为Jezyki-JOIN选择伪wampira，sprawnosc，通过伪wampira从Sprawnosci_-w组中计数*作为计数器，在jezyki.pseudo_-wampira=sprawnosc.pseudo_-wampira和jezyki.counter=sprawnosc.counter上使用sprawnosc作为sprawnosc您看到错误了吗？很抱歉，我在注释中遇到了编码问题。代码有类似于您的表格；第五行是jezyki@robocoder-Oracle不允许用户使用表别名，尽管它允许使用列别名。尝试删除该单词，使第5行变为t1，第9行变为t2。@AlexPoole:感谢您在我忙得没法回答时提供的帮助。我是按照您的方式完成的，但第5行第9列有一个错误，SQL命令没有正确结束SELECT pseudo_-wampira中的SELECT jezyki.pseudo_-wampira，sprawnosc.counter，通过伪wampira从Jezyki_-obce_-w组中计数*作为计数器作为Jezyki-JOIN选择伪wampira，sprawnosc，通过伪wampira从Sprawnosci_-w组中计数*作为计数器，在jezyki.pseudo_-wampira=sprawnosc.pseudo_-wampira和jezyki.counter=sprawnosc.counter上使用sprawnosc作为sprawnosc您看到错误了吗？很抱歉，我在注释中遇到了编码问题。代码有类似于您的表格；第五行是jezyki@robocoder-Oracle不允许用户使用表别名，尽管它允许使用列别名。试着去掉那个词，这样第5行就变成t1行，第9行变成t2行。@AlexPoole:谢谢你在我忙得没时间回复的时候帮了我的忙。

WITH jezyki as 
          (SELECT pseudo_wampira, COUNT(*) AS counter
            FROM Jezyki_obce_w
            GROUP BY pseudo_wampira
          )
    ,sprawnosc as 
         (SELECT pseudo_wampira, sprawnosc, COUNT(*) AS counter
          FROM Sprawnosci_w
         GROUP BY pseudo_wampira, sprawnosc 
         )
      SELECT jezyki.pseudo_wampira, sprawnosc.counter
        FROM jezyki,sprawnosc
       WHERE  jezyki.pseudo_wampira = sprawnosc.pseudo_wampira 
         AND  jezyki.counter = sprawnosc.counter