Parsing 从CSV中删除行

我有一个带有多个标题的csv文档，如：

"Date","RQ","PM","SME","Activity","Status code" "2/2/12","6886","D_WV","John Smith","Recent","2004" 然而，这给我留下了额外的数据，比如

data.csv:1"Date","RQ","PM","SME","Activity","Status code" data.csv:2"2/2/12","6886","D_WV","John Smith","Recent","2004"

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使用正确格式但不希望删除任何值的。非常感谢您的帮助。

选择字符串中的matchinfo对象可能会令人困惑。 这能满足你的需要吗

$m = gc textfile.txt
select-string data.csv -pattern $m -notmatch |
select -expand line

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我建议采用另一种方法来避免误报：

$m = Get-Content textfile.txt
Import-Csv data.csv `
  | ? { $m -notcontains $_."Status code" } `
  | Export-Csv output.csv -NoTypeInformation

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这非常有效。我不知道扩展线。非常感谢！：）

$m = gc textfile.txt
select-string data.csv -pattern $m -notmatch |
select -expand line

$m = Get-Content textfile.txt
Import-Csv data.csv `
  | ? { $m -notcontains $_."Status code" } `
  | Export-Csv output.csv -NoTypeInformation