Php 如何编写whmcs内部联接'；其中条件为'；

whmcs内部联接“何处条件”

两个表具有相同的字段

在where条件下如何区分表名

$where = array(
   "table1.lastname"=>array("sqltype"=>"LIKE","value"=>"Demo"),
   "table2.companyname"=>array("sqltype"=>"NEQ","value"=>""),
);

试过这个,

$table = "tblclients";
$fields = "id,firstname,lastname,domain";
$where = array(
   "lastname"=>array("sqltype"=>"LIKE","value"=>"Demo"),
   "companyname"=>array("sqltype"=>"NEQ","value"=>""),
);
$sort = "id";
$sortorder = "ASC";
$limits = "0,5";
$join = "tblhosting ON tblhosting.userid=tblclients.id";
$result = select_query($table,$fields,$where,$sort,$sortorder,$limits,$join);

如何在where条件下指定表名

$where = array(
   "table1.lastname"=>array("sqltype"=>"LIKE","value"=>"Demo"),
   "table2.companyname"=>array("sqltype"=>"NEQ","value"=>""),
);