Php 如何合并具有相同数据的连续子阵列？

我有这个阵列：

$opening_hours = array(
  'Monday' => array('09:00', '17:00'),
  'Tuesday' => array('09:00', '17:00'),
  'Wednesday' => array('08:00', '13:00'), 
  'Thursday' => array('09:00', '17:00'),
  'Friday' => array('09:00', '17:00'),
  'Saturday' => array('10:00', '16:00'),
  'Sunday' => array('Closed'),
);

我需要以某种方式将这些开放时间合并到阵列中，该阵列应如下所示：

$merged_opening_hours = array(
  'Monday - Tuesday' => array('09:00', '17:00'),
  'Wednesday' => array('08:00', '13:00'),
  'Thursday - Friday' => array('09:00', '17:00'),
  'Saturday' => array('10:00', '16:00');
  'Sunday' => array('Closed'),
);

---

有什么想法吗？

这应该适合你：

因此，基本上您只需在整个数组中循环，并检查下一个元素是否仍然设置，当前数组是否与下一个相同（这意味着它们的小时数相同）。如果是，则执行此操作，直到while循环返回false。这是什么代码：

$DayAmountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
    $DayAmountOfConsecutiveSameHours++;

if($DayAmountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

$dayCount += ($DayAmountOfConsecutiveSameHours - 1);

然后，如果有多个条目，则创建一个从一天到另一天的范围。这是什么代码：

$DayAmountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
    $DayAmountOfConsecutiveSameHours++;

if($DayAmountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

$dayCount += ($DayAmountOfConsecutiveSameHours - 1);

如果您只有1天的相同时间，只需将其添加到结果数组中即可。这是什么代码：

$DayAmountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
    $DayAmountOfConsecutiveSameHours++;

if($DayAmountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

$dayCount += ($DayAmountOfConsecutiveSameHours - 1);

根据相同的小时数可以跳过下一个数组元素。这是什么代码：

$DayAmountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
    $DayAmountOfConsecutiveSameHours++;

if($DayAmountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

$dayCount += ($DayAmountOfConsecutiveSameHours - 1);

完整代码：

<?php

    $opening_hours = [
            "Monday" => ["09:00", "17:00"],
            "Tuesday" => ["09:00", "17:00"],
            "Wednesday" => ["08:00", "13:00"], 
            "Thursday" => ["09:00", "17:00"],
            "Friday" => ["09:00", "17:00"],
            "Saturday" => ["10:00", "16:00"],
            "Sunday" => ["Closed"],
        ];


    $amountOfDays = count($opening_hours);
    $arrayKeys = array_keys($opening_hours);

    for($dayCount = 0; $dayCount < $amountOfDays; $dayCount++) {
        $DayAmountOfConsecutiveSameHours = 1;
        while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
            $DayAmountOfConsecutiveSameHours++;

        if($DayAmountOfConsecutiveSameHours > 1)
            $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];
        else
            $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

        $dayCount += ($DayAmountOfConsecutiveSameHours - 1);
    }

    print_r($result);

?>

---

@FrancescoAbeni我曾尝试循环使用$opening_hours数组，并检查数组的下一个元素是否与当前元素相同，但不知何故，这没有起作用。Rizier123做了我需要的解释。谢谢你的解释和整个功能。它确实能正常工作。在问这个问题之前，我已经开始比较数组的下一个元素和当前元素，在我的例子中，它不起作用。大卫更新了我的答案，把一切都简化了一点。希望它更容易理解