Php 在Mysql中使用where和Like子句过滤数据

我在mysql数据库中使用LIKE关键字过滤数据。这是以下查询：

Select c.c_id, c.c_name, slab, 
COUNT(c.c_id) as tot_visit,
SUM(t.bill) as tot_revenue, c.priority, c.ratings 
From tbl_customer c
inner join tbl_transaction t on c.c_id=t.c_id
group by c.c_id 
Where r_id="r1" AND c.slab LIKE "%teen%"

$qry = mysql_query('Select c.c_id, c.c_name, c.slab, 
COUNT(c.c_id) as tot_visit,
SUM(t.bill) as tot_revenue, c.priority, c.ratings 
From tbl_customer c
inner join tbl_transaction t on c.c_id=t.c_id
Where r_id="r1" AND "'.$str.'" 
group by c.c_id');

---

当我删除此->和c.职业，如“%teen%”时，请尝试在

groupby

Select c.c_id, c.c_name, slab, 
COUNT(c.c_id) as tot_visit,
SUM(t.bill) as tot_revenue, c.priority, c.ratings 
From tbl_customer c
inner join tbl_transaction t on c.c_id=t.c_id
Where r_id="r1" AND c.occupation LIKE "%teen%"
group by c.c_id 

---

在以下查询中：

Select c.c_id, c.c_name, slab, 
COUNT(c.c_id) as tot_visit,
SUM(t.bill) as tot_revenue, c.priority, c.ratings 
From tbl_customer c
inner join tbl_transaction t on c.c_id=t.c_id
group by c.c_id 
Where r_id="r1" AND c.slab LIKE "%teen%"

$qry = mysql_query('Select c.c_id, c.c_name, c.slab, 
COUNT(c.c_id) as tot_visit,
SUM(t.bill) as tot_revenue, c.priority, c.ratings 
From tbl_customer c
inner join tbl_transaction t on c.c_id=t.c_id
Where r_id="r1" AND "'.$str.'" 
group by c.c_id');

这句话模棱两可：

Where r_id="r1" AND "'.$str.'" 

由于变量$str如下所示：

Where r_id="r1" AND '.$str.' 

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感谢Stackoverflow提供的所有帮助。

将where子句置于group by子句之前您的where条件不满足任何条件，这就是为什么返回空结果集

where r\u id=“r1”

-

r\u id

可能应该是

t.r\u id

<“选择”中的“代码>板”也没有前缀。可能没有与您的条件匹配的行。