Warning: file_get_contents(/data/phpspider/zhask/data//catemap/0/laravel/11.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Php 如何在Laravel 5.5中保存同名属性值_Php_Laravel - Fatal编程技术网

Php 如何在Laravel 5.5中保存同名属性值

Php 如何在Laravel 5.5中保存同名属性值,php,laravel,Php,Laravel,在Laravel 5.5中保存同名属性的方法是什么?如果我在foreach循环中对它们进行分组,并将save方法放在何处,我就不会这样做 <input type="text" name="aka" value="The Magnificent" /> @foreach ($listTalkOperationTime as $data) <input type="number" name="startHours[]"value="{{ $data->start

在Laravel 5.5中保存同名属性的方法是什么?如果我在foreach循环中对它们进行分组,并将save方法放在何处,我就不会这样做

<input type="text" name="aka" value="The Magnificent" />    
@foreach ($listTalkOperationTime as $data)
   <input type="number" name="startHours[]"value="{{ $data->starthour }}" />
   <input type="number" name="startMins[]" value="{{ $data->startmin }}" />
   <input type="number" name="endHours[]" value="{{ $data->endhour }}" />
   <input type="number" name="endMins[]" value="{{ $data->endmin }}" />
   <button type="button">Submit</button>
@endforeach

foreach($request->startHours as$so){$model->startHours=$so;}
将假定
N
表中
startHours
列的数量。这是不可能的。您应该在问题中添加db结构。可能您需要关系。为什么您的输入是
array
$model = new User;
$model->aka = $request->aka;
foreach ($request->startHours as $so) {
  $model->starthours = $so;
}
foreach ($request->startMins $sm) {
  $model->starthours = $sm;
}
...
$model->save()