PHP无法动态构建PDO查询。
因此,我尝试使用PDO(一种动态的mysql查询)来构建和准备。这是我的代码和调试信息PHP无法动态构建PDO查询。,php,pdo,Php,Pdo,因此,我尝试使用PDO(一种动态的mysql查询)来构建和准备。这是我的代码和调试信息 $allowed_filters = array('hotels.star_rating', 'countries.id'); $where = 'WHERE 1 '; if (!empty($data['filters'])){ $where = 'WHERE'; foreach ($data['filters'] as $field => $value){ if (
$allowed_filters = array('hotels.star_rating', 'countries.id');
$where = 'WHERE 1 ';
if (!empty($data['filters'])){
$where = 'WHERE';
foreach ($data['filters'] as $field => $value){
if (in_array($field, $allowed_filters)){
$where .= " $field = :$field &&";
}
else unset($data['filters'][$field]);
}
$where = rtrim($where, '&&');
$where = ($where == 'WHERE')? 'WHERE 1 ' : $where;
}
$st = $this->db->prepare("
SELECT
hotels.code,
hotels.name as name,
hotels.star_rating,
hotels.description,
hotels.cover_image,
countries.name as country,
cities.name as city
FROM
hotels JOIN cities ON cities.id = hotels.city_id
join countries on countries.id = cities.country_id
$where
");
$st->execute($data['filters']);
var_dump($st->fetch());
就在$st->execute$data['filters']行之前,我转储了$st和$data['filters']。数值如下所示
价值$st
PDOStatement Object
(
[queryString] =>
SELECT
hotels.code,
hotels.name as name,
hotels.star_rating,
hotels.description,
hotels.cover_image,
countries.name as country,
cities.name as city
FROM
hotels JOIN cities ON cities.id = hotels.city_id
join countries on countries.id = cities.country_id
WHERE
hotels.star_rating = :hotels.star_rating &&
countries.id = :countries.id
)
$data['filters'的值
Array
(
[hotels.star_rating] => 4 stars
[countries.id] => 5
)
PDO引发异常并失败,出现以下错误
SQLSTATE[HY093]:参数编号无效:未定义参数'
帮助?您忘记了$data['filters'键中的冒号。应该是:
Array
(
[:hotels.star_rating] => 4 stars
[:countries.id] => 5
)
没错。你能解释一下为什么有时候它不用冒号吗?例如,这很好$st=$dbh->准备“从id=:id'的酒店选择*”$st->Executarray'id'=>1;var_dump$st->fetch;