Php 对象在持久化之前设置为null-ZF2/doctor

我对zend框架2和条令2比较陌生，所以请耐心听我说

我有两个实体——账单和付款。我正在尝试创建一个付款表单，以便我可以对单个账单进行付款。问题是，当我去付款时，我犯了一个严重的错误

可捕获致命错误：参数1传递给 Application\Entity\Payment:：addBill（）必须是的实例 Application\Entity\Bill，给定为空，在中调用 /var/www/zend/module/Bill/src/Bill/Controller/BillController.php

因此，我在

$bill_obj

上进行var转储，得到以下结果：

//VAR DUMP RESULTS
object(Application\Entity\Bill)[337]
  protected 'inputFilter' => null
  protected 'id' => int 5
  protected 'creditor' => string 'sdafddddddd' (length=11)
  protected 'type' => string '123fasdfsadfdd' (length=14)

$bill\u obj

是bill的一个实例。如果我将

$bill\u id

设置为

5

，它会工作

public function paymentAction()
{
    $bill_id  = (int) $this->params()->fromRoute('id');
    $bill_obj = $this->getEntityManager()->find('Application\Entity\Bill', $bill_id);
    var_dump($bill_obj);
    $form     = new PaymentForm();
    $request  = $this->getRequest();
    if ($request->isPost()) {
        $payment = new Payment();
        $payment->addBill($bill_obj);
        $form->setInputFilter($payment->getInputFilter());
        $form->setData($request->getPost());

        if ($form->isValid()) {
            $payment->exchangeArray($form->getData());
            $this->getEntityManager()->persist($payment);
            $this->getEntityManager()->flush();

            // Redirect to list of bills
            return $this->redirect()->toRoute('bill');
        }
    }
    return array('form' => $form);
}

这是支付实体：

class Payment implements InputFilterAwareInterface 
{
protected $inputFilter;

/**
 * @ORM\Id
 * @ORM\Column(type="integer");
 * @ORM\GeneratedValue(strategy="AUTO")
 */
protected $id;

/**
 * @ORM\ManyToOne(targetEntity="Bill", inversedBy="id")
 */
protected $bill;

/**
 * @ORM\Column(type="datetime")
 */
protected $date;

/**
 * @ORM\Column(type="float")
 */
protected $amount;

/**
 * Magic getter to expose protected properties.
 *
 * @param string $property
 * @return mixed
 */

票据实体：

class Bill implements InputFilterAwareInterface 
{
protected $inputFilter;

/**
 * @ORM\Id
 * @ORM\Column(type="integer");
 * @ORM\GeneratedValue(strategy="AUTO")
 */
protected $id;

/**
 * @ORM\Column(type="string")
 */
protected $creditor;

/**
 * @ORM\Column(type="string")
 */
protected $type;

---

我想出了一个解决办法。我设置了一个以billid为值的隐藏字段，并在find方法中使用它。我仍然想知道为什么我不能从路线上获得id。如果有人知道，请评论。谢谢

public function paymentAction()
{

    $bill_id = (int) $this->params()->fromRoute('id');

    $form = new PaymentForm();

    $request = $this->getRequest();
    if ($request->isPost()) {

        $data = $request->getPost();
        $payment = new Payment();
        $bill_obj = $this->getEntityManager()->find('Application\Entity\Bill', $data['bill_id']);
        $payment->addBill($bill_obj);
        $form->setInputFilter($payment->getInputFilter());
        $form->setData($request->getPost());

        if ($form->isValid()) {
            $payment->exchangeArray($form->getData());
            $this->getEntityManager()->persist($payment);
            $this->getEntityManager()->flush();

            // Redirect to list of bills
            return $this->redirect()->toRoute('bill');
        }
    }
    return array('form' => $form, 'id' => $bill_id);
}

---

var转储没有手动设置

$bill\u id

？