Php 遍历数组以比较当前和下一个键索引

我遍历一个数组来比较当前和下一个键索引，以检查值是否相同。 我制作了两个数组：第一个数组，当条件满足时——当前和下一个键索引的值相同；第二个数组是数组的剩余元素

但问题是在第二个数组中，我总是从第一个数组中得到一个元素

[special_days_nested_array] => Array
        (
            [0] => Array
                (
                    [day_name] => Tue
                    [start_time] => 05:00 am
                    [end_time] => 08:00 pm
                )

            [1] => Array
                (
                    [day_name] => Fri
                    [start_time] => 06:00 am
                    [end_time] => 10:00 pm
                )

            [2] => Array
                (
                    [day_name] => Sat
                    [start_time] => 12:00 am
                    [end_time] => 08:54 pm
                )

            [3] => Array
                (
                    [day_name] => Sun
                    [start_time] => 12:00 am
                    [end_time] => 08:54 pm
                )

        )

这是我用来比较相同值的数组

$j = 0;
        foreach($data_set->special_days_nested_array as $key => $value){

            if(($data_set->special_days_nested_array[$j]['start_time'] == $data_set->special_days_nested_array[$j+1]['start_time']) && ($data_set->special_days_nested_array[$j]['end_time'] == $data_set->special_days_nested_array[$j+1]['end_time']) ) {
                    //Days Array
                    $data_set->special_days_same_time_array[] = $data_set->special_days_nested_array[$j]['day_name'];
                    $data_set->special_days_same_time_array[] = $data_set->special_days_nested_array[$j+1]['day_name'];
                    //timings
                    $data_set->special_timings_same_time = $data_set->special_days_nested_array[$j]['start_time'].' - '.$data_set->special_days_nested_array[$j]['end_time']; 

            }

            else{
                $data_set->special_time_different_time_array[$data_set->special_days_nested_array[$key]['day_name']]['day_name'] =  $data_set->special_days_nested_array[$key]['day_name'];
                $data_set->special_time_different_time_array[$data_set->special_days_nested_array[$key]['day_name']]['start_time'] = $data_set->special_days_nested_array[$key]['start_time'];
                $data_set->special_time_different_time_array[$data_set->special_days_nested_array[$key]['day_name']]['end_time'] = $data_set->special_days_nested_array[$key]['end_time'];
            }
            $j++;

        }

在这里，我遍历上面的数组并比较当前元素和下一个元素

这是我在成功比较中得到的数组

[special_days_same_time_array] => Array
        (
            [0] => Sat
            [1] => Sun
        )

    [special_timings_same_time] => 12:00 am - 08:54 pm

这是我从else条件中获得的数组：

[special_time_different_time_array] => Array
        (
            [Tue] => Array
                (
                    [day_name] => Tue
                    [start_time] => 05:00 am
                    [end_time] => 08:00 pm
                )

            [Fri] => Array
                (
                    [day_name] => Fri
                    [start_time] => 06:00 am
                    [end_time] => 10:00 pm
                )

            [Sun] => Array
                (
                    [day_name] => Sun
                    [start_time] => 12:00 am
                    [end_time] => 08:54 pm
                )

        )

在这个数组中，前两个元素是正确的，但我得到的第三个元素是不正确的

---

我无法找出确切的问题。

由于循环实现不正确，数组的绑定元素有问题。这是因为对于最后一个元素，没有第j+1个元素，所以您将始终输入条件的else分支

此外，还可以将常规for语法与foreach语法混合使用。对于这种情况，我建议您使用简单明了的for operator：

    for($j = 0; $j < count(data_set->special_days_nested_array)-1; $j++){

        if(($data_set->special_days_nested_array[$j]['start_time'] == $data_set->special_days_nested_array[$j+1]['start_time']) && ($data_set->special_days_nested_array[$j]['end_time'] == $data_set->special_days_nested_array[$j+1]['end_time']) ) {
                //Days Array
                $data_set->special_days_same_time_array[] = $data_set->special_days_nested_array[$j]['day_name'];
                $data_set->special_days_same_time_array[] = $data_set->special_days_nested_array[$j+1]['day_name'];
                //timings
                $data_set->special_timings_same_time = $data_set->special_days_nested_array[$j]['start_time'].' - '.$data_set->special_days_nested_array[$j]['end_time']; 

        }

        else{
            $data_set->special_time_different_time_array[$data_set->special_days_nested_array[$j]['day_name']]['day_name'] =  $data_set->special_days_nested_array[$j]['day_name'];
            $data_set->special_time_different_time_array[$data_set->special_days_nested_array[$j]['day_name']]['start_time'] = $data_set->special_days_nested_array[$j]['start_time'];
            $data_set->special_time_different_time_array[$data_set->special_days_nested_array[$j]['day_name']]['end_time'] = $data_set->special_days_nested_array[$j]['end_time'];
        }

    }

---

所以你想要[day_name]=>Sat[start_time]=>12:00 am[end_time]=>08:54 pm作为第三个元素？不，根据数组，不应该有第三个元素。因为两天——周六、周日的时间相同，周二、周五的时间不同。