Php MySQL数据中的线图

这是我的代码，我想在其中使用MySQL中的数据创建一个折线图。如果我给数组一个fiext值，它会生成图形，但是现在使用查询，它不会显示任何东西，那么任何帮助都会被感激

<?php
function linegraph ($arrval) 
{
$arrval;
$height = 260;
$width = 330;
$im = imagecreate($width,$height);
$white = imagecolorallocate($im,255,255,255);
$gray = imagecolorallocate($im,200,200,200);
$black = imagecolorallocate($im,0,0,0);
$red = imagecolorallocate($im,255,0,0);
$x = 21;
$y = 11;
$num = 0;
while(($x <= $width) && ($y <= $height))
{
    $prcnt = ((($height-50)-($y-1))/($height-60))*100;
    imageline($im, 21, $y, $width-10, $y, $gray);
    imageline($im, $x, 11, $x, $height-50, $gray);
    imagestring($im,2,1,$y-10,$prcnt.'%',$red);
    imagestring($im,2,$x-3,$height-40,$num,$red);
    $x += 30;
    $y += 20;
    $num++;
}
$tx = 20;
$ty = 210;
foreach($arrval as $values)
{
    $cx = $tx + 30;
    $cy = 200-$values;
    imageline($im,$tx,$ty,$cx,$cy,$red);    
    imagestring($im,5,$cx-3,$cy-13,'.',$red);
    $ty = $cy;
    $tx = $cx;
}
imageline($im, 20, 11, 20, $height-50, $black);
imageline($im, 20, $height-49, $width-10, $height-49, $black);
return imagepng($im);
}
include ('/dbcon.php');
$dataarray = array();
$qr = "SELECT * FROM indicator WHERE indicatorid = '83';";
$res = mysql_query($qr);
if($res)
{
    $Data = mysql_fetch_array($res);
    $topicid = $Data['topicid'];
    $indid = 83;
    $couid = 8;
    $year = 2011-10;
    for ($count=0; $count < 10; $count ++)
    {
        $qrdb = "SELECT value FROM databank WHERE topicid = '$topicid', indicatorid = '$indid', countryid = '$couid', yearid = '$year';";
        $result = mysql_query($result);
        if ($result)
        {
            $DDB = mysql_fetch_array($result);
            $dataarray[$count] = $DDB['value'];
        } else {
            echo "Data cannot be fetched form Databank";
        }
    }
}
else
{
    echo "MYSQL query Fail";
}
linegraph($dataarray);
?>

---

你的询问有错误

SELECT value FROM databank 
WHERE topicid = '$topicid', 
indicatorid = '$indid', 
countryid = '$couid', 
yearid = '$year';"

当您进行更新时，当您进行必须使用的选择时，您应该使用

试着这样做：

SELECT value FROM databank 
WHERE topicid = '$topicid' and 
indicatorid = '$indid' and
countryid = '$couid'and 
yearid = '$year';"

---

在这个问题上，几乎没有足够的信息能够精确地回答，但是看起来你可能想考虑使用MySqLyFuffChyAsOC代替MySqLyFiffChina数组。实际上，您可能不想使用这两个函数中的任何一个，因为它们都已弃用。。。