Php symfony更改属性'；对于'；表格标签

我在谷歌上搜索，但找不到如何更改（附加）表单标签中的“for”属性

{{ form_widget(form.star,{'id':'rating-input-1-5','attr':{'class':'rating-input'}}) }}
                                    {{ form_label(form.star,null,{'label_attr':{'class':'rating-star','for':'rating-input-1-5'}}) }}
                                    {{ form_widget(form.star,{'id':'rating-input-1-4','attr':{'class':'rating-input'}}) }}
                                    {{ form_label(form.star,null,{'label_attr':{'class':'rating-star','for':'rating-input-1-4'}}) }}
                                    {{ form_widget(form.star,{'id':'rating-input-1-3','attr':{'class':'rating-input'}}) }}
                                    {{ form_label(form.star,null,{'label_attr':{'class':'rating-star','for':'rating-input-1-3'}}) }}
                                    {{ form_widget(form.star,{'id':'rating-input-1-2','attr':{'class':'rating-input'}}) }}
                                    {{ form_label(form.star,null,{'label_attr':{'class':'rating-star','for':'rating-input-1-2'}}) }}
                                    {{ form_widget(form.star,{'id':'rating-input-1-1','attr':{'class':'rating-input'}}) }}
                                    {{ form_label(form.star,null,{'label_attr':{'class':'rating-star','for':'rating-input-1-1'}}) }}

我希望表单标签指向我的表单小部件的id

可能吗

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感谢您的回答

尝试更改

表单标签

呼叫

{{ form_label(form.star,null,{'id':'rating-input-1-5', 'label_attr':{'class':'rating-star'}}) }}

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尝试使用集合表单类型